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Vikentia [17]
4 years ago
9

How do you solve 12a - 14a = 8?

Mathematics
2 answers:
likoan [24]4 years ago
5 0
12a-14a=8\ \ \ \ |Subtract\ similar\ factors\\\\
-2a=8\ \ \ |Divide\ by\ -2\\\\
a=-4\\\\Solution\ is\ a=-4.
BigorU [14]4 years ago
3 0
-12a - 14a = -2a
so then it would be -2a = 8
then divide. 8 / -2 = -4

a=-4
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In what ways do the agati and the Brazil nut tree depend on each other ​
nirvana33 [79]

Answer:

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3 years ago
The area of a rectangular garden is 3927cm . If the width of the garden is 51 m , what is its length?
Galina-37 [17]

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6 0
3 years ago
2x-5y=9<br> 3x+4y=2<br> solve the simultaneous equations
wariber [46]

\huge\boxed{x=2;\ y=-1}

\left\{{{2x-5y=9}\atop{3x+4y=2}}\right

First, we will solve the second equation for x. Subtract 4y from both sides of the second equation.

3x=2-4y

Divide both sides of the second equation by 3.

x=\frac{2}{3}-\frac{4}{3}y

\left\{{{2x-5y=9}\atop{x=\frac{2}{3}-\frac{4}{3}y}}\right

Substitute the value of x from the second equation into the first.

\left\{{{2(\frac{2}{3}-\frac{4}{3}y)-5y=9}\atop{x=\frac{2}{3}-\frac{4}{3}y}}\right

2(\frac{2}{3}-\frac{4}{3}y)-5y=9

We will solve the first equation for y.

Distribute the 2 to the (\frac{2}{3}-\frac{4}{3}y).

\frac{4}{3}-\frac{8}{3}y-5y=9

Combine the like terms.

\frac{4}{3}-\frac{23}{3}y=9

Add \frac{4}{3} on both sides.

-\frac{23}{3}y=9-\frac{4}{3}

-\frac{23}{3}y=\frac{23}{3}

Divide both sides by \frac{23}{3}.

-y=1

Multiply both sides by -1.

y=\boxed{-1}

Substitute the value of y into the second equation.

\left\{{{y=-1}\atop{x=\frac{2}{3}-\frac{4}{3}y}}\right

x=\frac{2}{3}-\frac{4}{3}*-1

Multiply.

x=\frac{2}{3}+\frac{4}{3}

Add.

x=\frac{6}{3}

x=\boxed{2}

5 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7Bx-8%7D" id="TexFormula1" title="\sqrt[4]{x-8}" alt="\sqrt[4]{x-8}" align="abs
gavmur [86]
X=8 is the correct answer
3 0
3 years ago
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