Answer:
The price of
1 adult ticket = $15
1 student ticket = $9
Step-by-step explanation:
Let
The price of adult tickets be represented by a
The price of student tickets be represented by s
Therefore:
On the first day of ticket sales the school sold 4 adult tickets and 10 student tickets for a total of $150.
4a + 10s = $150.... Equation 1
The school took in $105 on the second day by selling 1 adult ticket and 10 student tickets.
a + 10s = $105.... Equation 2
a = $105 - 10s
Therefore, we substitute : $105 - 10s = a in Equation 1
4a + 10s = $150.... Equation 1
4($105 - 10s) + 10s = $150
$420 - 40s + 10s = $150
Collect like terms
- 40s + 10s = $150 - $420
-30s = -$270
Divide both sides by -30
-30s/-30 = -$270/-30
s = $9
We find a
a = $105 - 10s
a = $105 - 10($9)
a = $105 - $90
a = $15
Therefore, the price of
1 adult ticket = $15
1 student ticket = $9
Answer:
B:yes
Explanation:
Label the point 3 would be x and 9 would be y. Substitute these points into the equation were it corresponds.
Y= 2x+3
9=2(3)+3
9=6+3
9=9
Y=4x-3
9=4(3)-3
9=12-3
9=9
Hope this helps!!
You would divide 34 by 40, giving you the decimal number of:
0.85
you would then multiply by 100, moving the decimal point two places to the right.
andy got 85%
hope this helped, xx
Answer: In other cases, guessing the correct answer is not so easy.Give students the equation 4 + 1 = 7 − 2, and ask them the following questions: 1. we get another equation that is also true. −3. 2. = 2 . 2. MP.8 could say, “Add 100 to both.
Step-by-step explanation: