Answer:
Thank you so much!!
Explanation:
They deleted my first answer. I don't know why?
Answer:
Replicated chromosomes at metaphase I = 66
Sister chromatids at metaphase I = 66 x 2 = 132
Sister chromatids at prophase II = 66
Chromosomes in each sperm cells = 33
Explanation:
Metaphase I of meiosis I would have 66 replicated chromosomes in the testicular cells of the bird. Each of the replicated chromosomes would have two sister chromatids. So, a total of 66 replicated chromosomes would have 66 x 2 = 132 sister chromatids.
Due to segregation of homologous chromosomes towards opposite poles in anaphase I, each daughter cell formed by the end of meiosis I would have 33 replicated chromosomes. So, each of the daughter cells would have a total 33 x 2 = 66 sister chromatids at prophase II.
Since meiosis II maintains the chromosome number, each sperm cell formed by the end of meiosis II would have 33 chromosomes.
Answer:
it results in 2 exact copies of the original dna strand
Explanation:
The dna is unzipped and the two strands are used as templates for the 2 new dna molecules
Matter cannot be generated or destroyed, according to the Law of Conservation of Matter. Because the same carbon atoms are recycled throughout the carbon cycle, it is an illustration of the Law.