Answer:
a. 60/61
Step-by-step explanation:
With reference angle A
base(b) = 60
hypotenuse (h) = 61
Now
Cos(A) = b / h
= 60/ 61
Answer:
p=i/rt
Step-by-step explanation:
its p= i over rt
True, because the dilation factor is less than one. This will result in the shape reducing.
Option C:
We can find the value of PR using law of cosines.
Solution:
Given data:
∠Q = 18°, r = 9.5, p = 6.0
To find which length could be find in the triangle:
Law of cosines:
![a^{2}=b^{2}+c^{2}-2 b c \cos A](https://tex.z-dn.net/?f=a%5E%7B2%7D%3Db%5E%7B2%7D%2Bc%5E%7B2%7D-2%20b%20c%20%5Ccos%20A)
Substitute a = q, b = r, c = p and A = Q
![q^{2}=r^{2}+p^{2}-2 r p \cos Q](https://tex.z-dn.net/?f=q%5E%7B2%7D%3Dr%5E%7B2%7D%2Bp%5E%7B2%7D-2%20r%20p%20%5Ccos%20Q)
If we substitute the values given, we can find q.
q = PR
![PR^{2}=r^{2}+p^{2}-2 r p \cos Q](https://tex.z-dn.net/?f=PR%5E%7B2%7D%3Dr%5E%7B2%7D%2Bp%5E%7B2%7D-2%20r%20p%20%5Ccos%20Q)
Hence we can find the value of PR using law of cosines.
Option C is the correct answer.
Simplifies to:
1.690196x+396.139706=2
Let's solve your equation step-by-step.
1.690196x+396.139706=2
Step 1: Subtract 396.139706 from both sides.
1.690196x+396.139706-396.139706=2-396.139706
1.690196x=-394.139706
Step 2: Divide both sides by 1.690196.
1.690196x/1.690196 -394.139706/1.690196
x= -233.191716
Answer: x= -233.191716