If the candidate only wants a 0.2% margin of error at a 95% confidence level, what size of sample is needed?
1 answer:
Answer:
n = 22
Step-by-step explanation:
Using
n = p(1-p)(Zc/E)²
From table E = 0.2 while p= 0.37
So substituting
We have n= 22.4
Thats a sample size of approximately 22
You might be interested in
Answer: First, you need to figure out 22 times 2 = 44. Then, you need to multiply the original ratio by 44 to get the answer.
Step-by-step explanation:
Is it a multiple choice question
Answer:
the answer is 32 units.
Step-by-step explanation:
Answer:
k76
Step-by-step explanation:
it is
