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3 years ago

Can someone help me out

Mathematics

2 answers:

fgiga [73]3 years ago

7 0

I don’t know for sure if I’m correct but I think it’s J (6)

joja [24]3 years ago

5 0

I believe that the answer is j 6

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The function that has an x-intercept of -2 and a y-intercept of -2/3.

yarga [219]

I got you

Step-by-step explanation:

y=-2/3x-2

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3 years ago

How do you find an exponential growth model

ipn [44]

Answer:

When the line of the graph is going up

Step-by-step explanation:

When the line is going down that means its a exponential decay :)

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2 years ago

What is the value of n in the equation 3n + 2(n + 2) = 9n + 12?

Alex777 [14]

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3 years ago

Find the highest common factor of 28 and 210 Step by step Please help

Yuri [45]

Hello there!

To find the GCF, we must list all the factors and then just spot the greatest factor.

28: 1, 2, 4, 7, 14, 28.

210 1, 2, 3, 5, 6, 7, 10, 14, 15, 21, 30, 35, 42, 70.

So 14 is the GCF. Hope this helps you!

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7 0

2 years ago

Giving 100 points.

Nitella [24]

Answer:

1. Cost per customer: 10 + x

Average number of customers: 16 - 2x

$\textsf{2.} \quad -2x^2-4x+160\geq 130$

3. $10, $11, $12 and $13

Step-by-step explanation:

Given information:

$10 = cost of buffet per customer
16 customers choose the buffet per hour
Every $1 increase in the cost of the buffet = loss of 2 customers per hour
$130 = minimum revenue needed per hour

Let x = the number of $1 increases in the cost of the buffet

Part 1

Cost per customer: 10 + x

Average number of customers: 16 - 2x

Part 2

The cost per customer multiplied by the number of customers needs to be at least $130. Therefore, we can use the expressions found in part 1 to write the inequality:

$(10 + x)(16 - 2x)\geq 130$

$\implies 160-20x+16x-2x^2\geq 130$

$\implies -2x^2-4x+160\geq 130$

Part 3

To determine the possible buffet prices that Noah could charge and still maintain the restaurant owner's revenue requirements, solve the inequality:

$\implies -2x^2-4x+160\geq 130$

$\implies -2x^2-4x+30\geq 0$

$\implies -2(x^2+2x-15)\geq 0$

$\implies x^2+2x-15\leq 0$

$\implies (x-3)(x+5)\leq 0$

Find the roots by equating to zero:

$\implies (x-3)(x+5)=0$

$x-3=0 \implies x=3$

$x+5=0 \implies x=-5$

Therefore, the roots are x = 3 and x = -5.

Test the roots by choosing a value between the roots and substituting it into the original inequality:

$\textsf{At }x=2: \quad -2(2)^2-4(2)+160=144$

As 144 ≥ 130, the solution to the inequality is between the roots:

-5 ≤ x ≤ 3

To find the range of possible buffet prices Noah could charge and still maintain a minimum revenue of $130, substitute x = 0 and x = 3 into the expression for "cost per customer.

[Please note that we cannot use the negative values of the possible values of x since the question only tells us information about the change in average customers per hour considering an increase in cost. It does not confirm that if the cost is reduced (less than $10) the number of customers increases per hour.]

Cost per customer:

$x =0 \implies 10 + 0=\$10$

$x=3 \implies 10+3=\$13$

Therefore, the possible buffet prices Noah could charge are:

$10, $11, $12 and $13.

8 0

2 years ago