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Tom [10]
3 years ago
5

Can someone help me out

Mathematics
2 answers:
fgiga [73]3 years ago
7 0
I don’t know for sure if I’m correct but I think it’s J (6)
joja [24]3 years ago
5 0
I believe that the answer is j 6
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bobby pays a $25 membership free to join YMCA gym. This gym allows members to attend any exercise class for only $4. The linear
blagie [28]

Answer:

Step-by-step explanation:

T = 4c + 25....where c = # of classes and T = total cost

2 classes...so sub in 2 for c and solve for T

T = 4(2) + 25

T = 8 + 25

T = 33 <==== with 2 classes ,its $ 33

4 classes....so sub in 4 for c and solve for T

T = 4(4) + 25

T = 16 + 25

T = 41 <==== with 4 classes, its $ 41

8 classes....sub in 8 for c

T = 4(8) + 25

T = 32 + 25

T = $ 57 <==== with 8 classes, its $ 57

10 classes...sub in 10 for c

T = 4(10) + 25

T = 40 + 25

T = 65 <===== with 10 classes, its $ 65

7 0
3 years ago
A skateboarding ramp is 12 in. high and rises at an angle of 21​°. How long is the base of the​ ramp? Round to the nearest inch.
bagirrra123 [75]

Answer:

the base of the ramp is 31 inches long.

Step-by-step explanation:

c = a/sin(α)

= 33.48514

b = √c2 - a2

= √33.4851373155042 - 122

= √977.25442103816

= 31.26107

3 0
2 years ago
What does the solution to an equation with one solution look like?
mihalych1998 [28]
I believe it's b. Hope this helps
3 0
3 years ago
I need help on what the area of the shape is because they didn’t tell us how to find it
Leto [7]

Answer:

The area of the shape (trapezoid) is 55 square feet.

Step-by-step explanation:

The formula to get the area of a trapezoid is ((b_{1} +b_{2} )/2)*h . b1 is one of the bases, b2 is the other and h is the height.

First, you need to find the average of the bases:

          (15+7=22)/2=11

Then, you multiply that by the height.

          11*5=55

Lastly, you add the units.

          55 square feet is the answer

8 0
3 years ago
Multiply the numbers and simplifty the answer 3x1 3/4
melamori03 [73]
2.25 is the answer you take 3 times 3/4 and you get 2.25
3 0
3 years ago
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