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3 years ago

Find m 5 Lines L and M are parallel

Mathematics

1 answer:

slavikrds [6]3 years ago

4 0

Answer:

142

Step-by-step explanation:

<38 and <6 are vertical angles so they both measure 38

<6 and <5 are same side interior angles so they add up to 180

knowing this, you can simply subtract 38 from 180 to find <5

180 - 38 = 142

You might be interested in

The height of a triangle is 4 cm more than twice its base. The area of the triangle is

il63 [147K]

Answer:

1/2 bh <= 168

1/2 b(2b+4) <= 168

or, use x instead of b if you want.

3 0

3 years ago

Use the distance formula to find the distance between cach pair of points. If necessary,

nata0808 [166]

Answer:

$d \approx 18.4$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra II

Distance Formula: $d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Step-by-step explanation:

Step 1: Define

Point C (-2, 6)

Point D (10, -8)

Step 2: Find distance d

Substitute: $d = \sqrt{(10+2)^2+(-8-6)^2}$
Add/Subtract: $d = \sqrt{(12)^2+(-14)^2}$
Exponents: $d = \sqrt{144+196}$
Add: $d = \sqrt{340}$
Simplify: $d =2 \sqrt{85}$
Evaluate: $d = 18.4391$
Round: $d \approx 18.4$

4 0

3 years ago

Independent random samples from two regions in the same area gave the following chemical measurements (ppm). Assume the populati

Basile [38]

Answer:

d. The interval contains only negative numbers. We cannot say at the required confidence level that one region is more interesting than the other.

Step-by-step explanation:

Hello!

You have the data of the chemical measurements in two independent regions. The chemical concentration in both regions has a Gaussian distribution.

Be X₁: Chemical measurement in region 1 (ppm)

Sample 1

n= 12

981 726 686 496 657 627 815 504 950 605 570 520

μ₁= 678

σ₁= 164

Sample mean X[bar]₁= 678.08

X₂: Chemical measurement in region 2 (ppm)

Sample 2

n₂= 16

1024 830 526 502 539 373 888 685 868 1093 1132 792 1081 722 1092 844

μ₂= 812

σ₂= 239

Sample mean X[bar]₂= 811.94

Using the information of both samples you have to determina a 90% CI for μ₁ - μ₂.

Since both populations are normal and the population variances are known, you can use a pooled standard normal to estimate the difference between the two population means.

[(X[bar]₁-X[bar]₂)± $Z_{1-\alpha /2}$ * $\sqrt{\frac{Sigma^2_1}{n1}+\frac{Sigma^2_2}{n_2} }$ ]

$Z_{1-\alpha /2}= Z_{0.95}= 1.648$

[(678.08-811.94)±1.648* $\sqrt{\frac{164^2}{12}+\frac{239^2}{16} }$ ]

[-259.49;-8.23]ppm

Both bonds of the interval are negative, this means that with a 90% confidence level the difference between the population means of the chemical measurements of region 1 and region 2 may be included in the calculated interval.

You cannot be sure without doing a hypothesis test but it may seem that the chemical measurements in region 1 are lower than the chemical measurements in region 2.

I hope it helps!

6 0

3 years ago

MULTIPLE CHOICE GEOMOTRY QUESTIOON

rosijanka [135]

Answer: D

Step-by-step explanation: Im vv sure, is this a test?

7 0

3 years ago

How much is 2 plus 9

Rama09 [41]

For this case we must represent the following expression algebraically, in addition to indicating its result: