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Kipish [7]
3 years ago
15

A communications tower is located on a plot

Mathematics
1 answer:
kykrilka [37]3 years ago
5 0

Answer: https://www.mercerislandschools.org/cms/lib3/WA01001855/Centricity/Domain/1249/Geo%20Week%2023.pdf

Hope this helps!

QuezoMartiinez

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In 3 billion repetitions of an experiment, a random event occurred in 500 million cases.
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5/6 is your other percentage
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The cost of 90 kg of rice is 4500. what is the cost of 2 quintal of rice?​
gayaneshka [121]

Answer:

The cost of 2 quintal of rice is $10,000.

Step-by-step explanation:

To determine the cost of 2 quintals of rice, knowing that 90 kilos of said product is worth $ 4,500, it is first necessary to establish the equivalence between quintals and kilograms. In this regard, a quintal is equivalent to 100 kilograms, so 2 quintals are equivalent to 200 kilos.

Now, to determine the cost per kilogram of rice, the following calculation is required:

4,500 / 90 = X

50 = X

Therefore, 1 kilogram of rice costs $ 50. Thus, since 200 x 50 equals 10,000, 2 quintals of rice will cost $ 10,000.

5 0
3 years ago
2) A company used 24 lemons to make 4 bottles of lemonade. Write an equation that
boyakko [2]

Answer:

Step-by-step explanation:

4 0
3 years ago
Solve for X<br> 14 = 3x + 2
Anit [1.1K]
Answer : 4

Explanation : you minus the 2 on both sides bc they have the same "last name" by doing this you get 12 on the left and elimination 2 on the right which leaves you with 12=3x. Divide 3 on both sides which 12/3 =4 and ur left with x. So the final equation is 4=x
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2 years ago
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Water is leaking out of an inverted conical tank at a rate of 6800 cubic centimeters per min at the same time that water is bein
Bad White [126]

Answer:

The rate at which water is being pumped into the tank is 13,913.27 cubic centimetre per minute

Step-by-step explanation:

Given that, the height of the conical tank is 13 meters and diameter is 3 meters.

Radius = \frac32 meters

\therefore \frac{radius }{height}=\frac {\frac{3}{2}}{13}

\Rightarrow \frac{radius }{height}=\frac {3}{26}

\Rightarrow radius=\frac {3}{26}\times height   ......(1)

The volume of the cone is   V=\frac13 \pi r^2 h

Now putting r=\frac{3}{26} h

V=\frac13 \pi (\frac3{26}h)^2 h

\Rightarrow V=\frac{3}{676} \pi h^3

Differentiating with respect to t

\frac{dV}{dt}=\frac{3}{676}\pi .3h^2 \frac{dh}{dt}

\Rightarrow \frac{dV}{dt}=\frac{9}{676}\pi h^2 \frac{dh}{dt}

Given that, the water level is rising at a rate of 17 cm per minute when the height 1 meter= 100 cm .i.e \frac{dh}{dt}=17 cm/min

Putting \frac{dh}{dt}=17  

\frac{dV}{dt}=\frac{9}{676}\pi h^2 \times 17

\frac{dV}{dt}|_{h=100}=\frac{9}{676}\pi (100)^2 \times 17

             ≈7,113 cubic centimetre per minute

The volume of water increases 7,113 cubic centimetre per minute while 6,800 cubic centimetre per minute is leaking out.

It means the required rate at which water is being pumped into the tank is

=(7,113+6,800)cubic centimetre per minute

=13,913 cubic centimetre per minute

           

   

4 0
3 years ago
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