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gogolik [260]
3 years ago
12

N - 8 > 5 A. n > 13 B. n > 3 C. n > - 3 D. n > -13

Mathematics
1 answer:
statuscvo [17]3 years ago
4 0

the answe is a- n>13

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Help me pls the questions are here
andreyandreev [35.5K]
3x + 7 = -x - 1
3x + 7 + = -1
4x + 7 = -1
4x = -1 - 7
4x = -8
x = -2

1 - 2x + 5 = 4x - 3
-2x + 6 = 4x - 3
6 = 4x - 3 + 2x
6 = 6x - 3
6 + 3 = 6x
9 = 6x
x = 6/9
x = 2/3

i helped you with the first two questions so you can see how you can solve it.

hope this helps, God bless!
6 0
3 years ago
Two numbers total 42 and have a difference of 8 find the two numbers
FinnZ [79.3K]
X+y = 42
x-y = 8
x = 8+y

Substitute it in 1st equation,
8+y+y=42
2y = 34
y = 17

Substitute it in 1st eq.,
x = 42-17 = 25

So, the two numbers are 25 & 17

Hope this helps!

5 0
3 years ago
Solve each equation using the Quadra<br>1. 4x2 +1 1x - 20=0<br>​
Tatiana [17]

Answer:

x= 12/11

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Help me plz
ololo11 [35]

Answer:

\left\{\begin{array}{l}y\le 4x\\y\ge 50\\25x+15y\ge 1975\end{array}\right.

Step-by-step explanation:

Let  x represent the number of lawns mowed and y represent the number of cars washed.

1. Since the number of cars that Beth wash is no more than four times the number of lawns Mike has scheduled to mow, you have that y\le 4x..

2. Beth will wash at least 50 cars, then y\ge 50.

3. Mike charges $25 each time he mows a yard, then he earns $25x for mowing x yards. Beth charges $15 for each car she washes, then she earns $15y for y cars washed. They need at least $1975, so

25x+15y\ge 1975.

4. A set of constraints to model the problem is

\left\{\begin{array}{l}y\le 4x\\y\ge 50\\25x+15y\ge 1975\end{array}\right.

4 0
2 years ago
From the following information, determine the average yearly depreciation.
Setler [38]
Average Yearly Depreciation = 291.67
4 0
3 years ago
Read 2 more answers
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