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quester [9]
3 years ago
7

Suppose that 76% of americans prefer coke to pepsi. A sample of 27 was taken. What is the probability that less than sixty perce

nt of the sample prefers coke to pepsi?
Mathematics
1 answer:
vodomira [7]3 years ago
5 0

Answer:

0.0403

Step-by-step explanation:

Given that 76% of americans prefer coke to pepsi.

Let x be the number of people who prefers coke to pepsi.

X is binomial as each trial is independent, and there are only two outcomes.

A sample of 27 was taken.

We have to find the probability that  less than sixty percent of the sample prefers coke to pepsi

60% of 27 = 27(0.6) = 16.2

Required probability = P(X

Hence prob=0.0403

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