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pentagon [3]
4 years ago
11

If g(x)=2[x]-1, what is g(-2,3)? A)-7 B)-5 C)-4 D)-3

Mathematics
2 answers:
Paha777 [63]4 years ago
6 0

the answer is -7 periodt

Nikitich [7]4 years ago
4 0
I would say d is the correct answer
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40 points fast For the following set of test scores, identify:
myrzilka [38]

Answer:

 The measure of center would this student want his teacher to use is the

median= {\bf 75}

Mean= {\bf 5}  ,  Mode={\bf 82}  , Range={\bf40}  and   Interquartile Range= {\bf 32}

Step-by-step explanation:

Given Data set= 50,55,70,75,82,82,90

Number of elements in data set= 7

To find Mean

The ‘Mean” is the average of a set of numbers.

The "Mean" is computed by adding all of the numbers in the data together and dividing by the number  of elements contained in the data set.

Mean= \frac{50 +55 +70 + 75 + 82 + 82 + 90} {7 }

Mean= \frac{504}{7}

Mean= 5

Median

The “Median” is the middle value of a set of ordered numbers.

Therefore Median=75

Mode

The "Mode" for a set of data is the value that occurs most often.

It is not uncommon for a data set to have more than one mode. This happens when two or more  elements occur with equal frequency in the data set.

Therefore Mode=82

Range

The "Range" is the difference between the largest value and smallest value in a set of data.

Range= 90-50

Range= 40

Interquartile Range

The “Interquartile Range” is the difference between smallest value and the largest value of the middle  50% of a set of data.

The "Interquartile Range" is from Q1 to Q3:

To find the interquartile range of a set of data:

The cut the list into four equal parts

. The quartiles are the “cuts”

The interquartile range is the distance between the two middle sets of data

Interquartile Range= Q_3-Q_1

Interquartile Range= 82-50

Interquartile Range= 32

5 0
3 years ago
What ordered pair describes the location of p
Hitman42 [59]

We conclude that the coordinates that describe the location of point P' are (4, -2).

<h3>What ordered pair describes the location of P'?</h3>

For a random point with coordinates (x, y), a reflection over the x-axis only changes the sign of the y-component. So the coordinates after the reflection are (x, -y).

In this case, the coordinates of point P are (4, 2), so if we apply a reflection over the x-axis to get the point P', the coordinates are:

(4, -2)

Where we just changed the sign of the y-component.

We conclude that the coordinates that describe the location of point P' are (4, -2).

If you want to learn more about rotations.

brainly.com/question/4289712

#SPJ1

4 0
2 years ago
Simplify the expression using long division. (10x2 – 85x – 10) ÷ (x – 8)
Lelechka [254]

Answer: 5 • (2x2 - 17x - 2)

 ———————————————————

        x - 8      

Step-by-step explanation:

Step by step solution :

Step  1  :

Equation at the end of step  1  :

 

Step  2  :

           10x2 - 85x - 10

Simplify   ———————————————

                x - 8      

Step  3  :

Pulling out like terms :

3.1     Pull out like factors :

  10x2 - 85x - 10  =   5 • (2x2 - 17x - 2)  

Trying to factor by splitting the middle term

3.2     Factoring  2x2 - 17x - 2  

The first term is,  2x2  its coefficient is  2 .

The middle term is,  -17x  its coefficient is  -17 .

The last term, "the constant", is  -2  

Step-1 : Multiply the coefficient of the first term by the constant   2 • -2 = -4  

Step-2 : Find two factors of  -4  whose sum equals the coefficient of the middle term, which is   -17 .

     -4    +    1    =    -3  

     -2    +    2    =    0  

     -1    +    4    =    3  

Observation : No two such factors can be found !!  

Conclusion : Trinomial can not be factored

8 0
3 years ago
Determine whether each point lies on the graph of the equation.(a) 2x - y - 3 = 0 (a) (1, 2)Yes, the point is on the graph.No, t
Neko [114]

Answer:

a) (1, 2) not on the graph.

b) (1, -1) is on the graph.

Step-by-step explanation:

Given the equation of the line as:

2x - y - 3 = 0

The points given are

a) (1, 2)

To determine whether it is on the graph of the line or not.

To do so, we can do 2 things:

1. Draw the graph and plot the point on the graph to check whether it is on the graph or not.

2. To put the point in the given equation of the line, whether the equation is satisfied or not.

For method 1: Kindly refer to the attached image of the line and point plotted.

Method 2:

Let us put x=1, y=2 in the Left Hand Side (LHS) of equation.

2\times 1 - 2 - 3\\\Rightarrow -3 \neq 0 , RHS

(1, 2) Not on the graph.

(b) (1, -1)

For method 1: Kindly refer to the attached image of the line and point plotted.

Method 2:

Let us put x=1, y=-1 in the Left Hand Side (LHS) of equation.

2\times 1 - (-1) - 3\\\Rightarrow 3-3 = 0 = RHS

(1, -1) is on the graph.

3 0
3 years ago
Can someone plz help me with this one problem only answer if Yk how to do it!!!!
ikadub [295]

Hello im really thinking its yes

so yes

hope its correct!!!

7 0
3 years ago
Read 2 more answers
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