F(x)=(-2/((x+y-2)^(1/2))-(x+y+2)^(1/2)
the only irrational part of this expression is the (x+y-2)^(1/2) in the denominator, so, to rationalize this, you multiply the numerator and denominator by the denominator, as well as the other parts of the expression
also, you must multiply the -sqrt(x+y+2) by sqrt(x+y-2)/sqrt(x+y-2) to form a common denominator
(-2)/(x+y-2)^(1/2)-(x+y+2)^(1/2)(x+y-2)^(1/2)/(x+y-2)^(1/2)
(common denominator)
(-2-(x^2+xy+2x+xy+y^2+2y-2x-2y-4))/(x+y-2)^(1/2)
(FOIL)
(-2-x^2-y^2-2xy+4)/(x+y-2)^(1/2)
(Distribute negative)
(-x^2-y^2-2xy+2)/(x+y-2)^(1/2)
(Simplify numerator)
(-x^2-y^2-2xy+2)(x+y-2)^(1/2)/(x+y-2)^(1/2)(x+y-2)^(1/2)
(Rationalize denominator by multiplying both top and bottom by sqrt)
(-x^2-y^2-2xy+2)((x+y-2)^(1/2))/(x+y-2)
(The function is now rational)
=(-x^2-y^2-2xy+2)(sqrt(x+y-2))/(x+y-2)
If the discriminant, b² - 4ac is<u> positive</u>
<h3>How to complete the statement?</h3>
From the question, we have the following equation of discriminant
The discriminant (d) is calculated as
d = b² - 4ac
The solutions of a quadratic equation are dependent on the following conditions
- If d = 0, the quadratic equation has 1 real solution
- If d < 0, the quadratic equation has imaginary solutions
- If d > 0, the quadratic equation has 2 different real solutions
This means that "d > 0, the quadratic equation has 2 different real solutions" implies that the discriminant is positive
Hence, the complete statement is (b) positive
Read more about discriminant at
brainly.com/question/64103
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Answer: x = 6
<u>Step-by-step explanation:</u>
2[3x - (4x - 6)] = 5(x - 6)
2[3x - 4x + 6] = 5x - 30
2[-x + 6] = 5x - 30
-2x + 12 = 5x - 30
<u>+2x </u> <u>+2x </u>
12 = 7x - 30
<u>+30 </u> <u> +30 </u>
42 = 7x
6 = x
Answer:
Hope this helps
Step-by-step explanation:
16 wide
Step-by-step explanation:
because i do 8 x 2
