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3 years ago

You roll a red, yellow and blue number cube. How many different rolls are possible?

Mathematics

2 answers:

melamori03 [73]3 years ago

6 0

Answer:

Step-by-step explanation:

multiply the amount of chances per cube by the amount of cubes

6x3=18

Braaainest??

ANEK [815]3 years ago

4 0

Answer:

18 rolls are possible.

Please mark me brainliest!

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A phone company charges a monthly fee of $35.00 and $0.10 per text message. Bridget wants to pay less than $1200.00 total for he

stiv31 [10]

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4 years ago

How to calculate Relative frequency

Andreyy89

To find the relative frequency, divide the frequency by the total number of data values. To find the cumulative relative frequency, add all of the previous relative frequencies to the relative frequency for the current row.

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3 years ago

Read 2 more answers

The depth of the snow at Yellowstone National Park in April at the lower geyser basin was normally distributed with a mean of 3.

Leona [35]

Answer:

$X =4.94\ in$

Step-by-step explanation:

For a standard normal distribution of mean $\mu_z = 0$ and $\sigma_z = 1$

the statistic $Z = \frac{X - \mu}{\sigma}$

In this problem we look for the value of X that is 2 standard deviations above the mean.

If there are two standard deviations above the mean, then, in the standard normal distribution, the statistic $Z = 2$ .

Then, we clear X.

$2 = \frac{X -\mu}{\sigma}\\\\2\sigma = X - \mu\\\\\2\sigma + \mu = X\\\\$

Where:

$\sigma=0.52\\\\\mu=3.9\\\\X = 2(0.52) + 3.9\\\\X =4.94$

7 0

3 years ago

Find the sum of the series given in sigma notation.

Kryger [21]

Answer:

Option b is correct 175

Step-by-step explanation:

n = 7

k = 6

3k -2 ------1

put k = 6 in above eq. for finding first term

a1 = 3(6) - 2 = 18 - 2 = 16

put k = 7 in above eq. for finding first term

a2 = 3(7) - 2 = 21 - 2 = 19

a3 = 3 (8) - 2 = 24 - 2 = 22

16, 19 , 22, ... //Arithmetic series formation

a1 = 16 , a2 = 19

d = a2 - a1 = 19 - 16 = 3 //Difference of first two terms

Using sum forumula for arithmetic series

sum = $\frac{n}{2}(2a1 + (n-1)d)$

= $\frac{7}{2}(2a1 + (7-1)d)$

= $\frac{7}{2}(2(16) + (6)3)$

= $\frac{7}{2}(32 + 18)$

= $\frac{7}{2}(50)$

= 7 * 25

= 175

4 0

3 years ago

A company that produces fine crystal knows from experience that 13% of its goblets have cosmetic flaws and must be classified as

Kisachek [45]

Answer:

(a) The probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b) The probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

Step-by-step explanation:

Let X = number of seconds in the batch.

The probability of the random variable X is, p = 0.31.

The random variable X follows a Binomial distribution with parameters n and p.

The probability mass function of X is:

$P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,3...$

(a)

Compute the probability that only one goblet is a second among six randomly selected goblets as follows:

$P(X=1)={6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=6\times 0.13\times 0.4984\\=0.3888$

Thus, the probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b)

Compute the probability that at least two goblet is a second among six randomly selected goblets as follows:

P (X ≥ 2) = 1 - P (X < 2)

$=1-{6\choose 0}0.13^{0}(1-0.13)^{6-0}-{6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=1-0.4336+0.3888\\=0.1776$

Thus, the probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c)

If goblets are examined one by one then to find four that are not seconds we need to select either 4 goblets that are not seconds or 5 goblets including only 1 second.

P (4 not seconds) = P (X = 0; n = 4) + P (X = 1; n = 5)

$={4\choose 0}0.13^{0}(1-0.13)^{4-0}+{5\choose 1}0.13^{1}(1-0.13)^{5-1}\\=0.5729+0.3724\\=0.9453$

Thus, the probability that at most five must be selected to find four that are not seconds is 0.9453.

8 0

3 years ago