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Gnesinka [82]
3 years ago
13

For the function f(1) = Pere, if P = 7 and r= 0.07, then what is the value of f(7)

Mathematics
2 answers:
Kipish [7]3 years ago
7 0

Answer:I think b

Step-by-step explanation:

Elis [28]3 years ago
3 0

Answer:

A. 11.4

Step-by-step explanation:

f(t) = Pe^{rt}

Data:

P = 7

r = 0.07

Calculation:

\begin{array}{rcl}f(t) & = &Pe^{rt}\\f(7)& = & 7 e^{(0.07 \times 7)}\\ & = & 7 e^{0.49}\\& \approx & 7 \times 1.632\\ & \approx & \mathbf{11.4}\\\end{array}

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dybincka [34]

Answer:

amplitude; \frac{2}{3}

Phase shift; \pi units right

Period;\frac{2\pi}{3}

Step-by-step explanation:

The given function is

y=-\frac{2}{3}\cos(3t-3\pi)

This function is of the form;

y=A\sin (Bt+C)

The period is given by:

|A|=|-\frac{2}{3}|= \frac{2}{3}

The period is given by:

T=\frac{2\pi}{|B|}= \frac{2\pi}{|3|}=\frac{2\pi}{3}

The phase shift is given by;

\frac{C}{B}=\frac{-\3pi}{3}=- \pi or \pi units right.

4 0
3 years ago
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Alex_Xolod [135]

Answer:

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Hope this helps)))

8 0
3 years ago
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Ilia_Sergeevich [38]
The stament are true I think
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3 years ago
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SOVA2 [1]
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Answer:

6

Step-by-step explanation:

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3 years ago
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