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hichkok12 [17]
4 years ago
6

According a person will devote 33 years to sleeping and watching TV. The number of years sleeping wil exceed the number of years

watching Over the many years will the person spend on each of these activities?
Mathematics
1 answer:
GaryK [48]4 years ago
5 0

Answer:

Do u have a picture? I want to help

Step-by-step explanation:

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Which of the following is a composite number that is divisible by both 2 and 3? A. 540 B. 351 C. 765 D. 1261
Kazeer [188]

The answer is A. 540

540 divided by 2 = 270

540 divided by 3 = 180

The number 540 is also composite, which is required in your answer.

The other numbers do not end in 0,2,4,6 or 8, which is required to be divided evenly by 2. And only answer choices A. B. and C. can be evenly divided by 3.

4 0
4 years ago
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What is the domain of y=4[x+2] ?
Diano4ka-milaya [45]
The domain of <span>y=4[x+2] is (-infinity, infinity) (also known as "all real numbers") because there is no value that x cannot equal. In other words, there is no value that would make y = undefined</span>
8 0
3 years ago
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Simplify the expression:<br> 5k2+3k2–4k2+k2
Lesechka [4]

Answer:

5k2

Step-by-step explanation:

5+3=8, 8-4=4, 4+1=5

7 0
3 years ago
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Assume that the Poisson distribution applies to the number of births at a particular hospital during a randomly selected day. As
kakasveta [241]

Answer:

0.9999985  = 99.99985% probability that in a day, there will be at least 1 birth.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval.

Assume that the mean number of births per day at this hospital is 13.4224.

This means that \mu = 13.4224

Find the probability that in a day, there will be at least 1 birth.

This is:

P(X \geq 1) = 1 - P(X = 0)

In which

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-13.4224}*13.4224^{0}}{(0)!} = 0.0000015

Then

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.0000015 = 0.9999985&#10;

0.9999985  = 99.99985% probability that in a day, there will be at least 1 birth.

7 0
3 years ago
5x-2y=30<br> Complete the missing value in the solution to the equation.<br> (8,__ )
vredina [299]

Answer:

the y value equals 5

Step-by-step explanation:

(x,y)so

plug in 8 for x

5(8)=40

40 -2y=30

subtract 40 from both sides

-2y=-10

divide by -2

y=5

5 0
4 years ago
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