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3 years ago

How do you do 18+2x=-8x+6(7+3x)

1 answer:

3 0

If this is a simultaneous equation then:
you should simplify it to get 18+2x=-8x+42+18x
Then simplify again and you get: 18+2x=10x+42
Next if you minus 2x from both sides you get: 18=8x+42
After that you minus 42 from both sides to get: -24=8x
Finally, divide both sides by 8 and you get: -3=x

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Y varies inversely with x. If y = -8 when x = -7, find the y when x=-4.

lora16 [44]

Answer:

y =-14

Step-by-step explanation:

Inverse variation is of the form

xy = k where k is a constant

(-7)(-8) = k

56 = k

The equation is

xy = 56

Let x = -4

(-4)y = 56

y = 56/-4

y =-14

8 0

3 years ago

Kevin can travel 22 1/2 miles in 1/3 hour. what is his average speed in miles per hour

klemol [59]

We know that speed * time = distance

Before we start we need to make sure the units for all three numbers are right

The time is 1/3 of a hour, 1/3*60 = 20 minutes

x * 20 = 22.5

x *2 * 10 = 22.5

2x = 2.25

x = 1.125

4 0

3 years ago

Read 2 more answers

The quadratic function g(x) = a.ca + bx+c has the

Mumz [18]

<em>The value of b is 14 and the value of c is 65</em>

<h2>Explanation:</h2>

The quadratic function is a function of the form:

$f(x)=ax^2+bx+c$

Here we know that the leading coefficient $a=1$ so we reduce our equation to:

$g(x)=x^2+bx+c$

The roots are those values at which $g(x)=0$

So:

$x^2+bx+c=0 \\ \\ First \ root: \\ \\ (-7+4i)^2+b(-7+4i)+c=0 \\ \\ (-7)^2-2(7)(4i)+(4i)^2-7b+4bi+c=0 \\ \\ 49-56i+16i^2-7b+4bi+c=0 \\ \\ \\ Simplifying: \\ \\ 49-56i+16(-1)-7b+4bi+c=0 \\ \\ 49-56i-16-7b+4bi+c=0 \\ \\ 33-56i-7b+4bi+c=0 \\ \\ \\$

$Second \ root: \\ \\ (-7-4i)^2+b(-7-4i)+c=0 \\ \\ (-1)^2(7+4i)^2+b(-7-4i)+c=0 \\ \\ (7)^2+2(7)(4i)+(4i)^2-7b-4bi+c=0 \\ \\ 49+56i+16i^2-7b-4bi+c=0 \\ \\ \\ Simplifying: \\ \\ 49+56i+16(-1)-7b-4bi+c=0 \\ \\ 49+56i-16-7b-4bi+c=0 \\ \\ 33+56i-7b-4bi+c=0$

So we have:

$(1) \ 33-56i-7b+4bi+c=0 \\ \\ (2) \ 33+56i-7b-4bi+c=0 \\ \\ \\ Subtract \ 2 \ from: \\ \\ 33-56i-7b+4bi+c-(33+56i-7b-4bi+c)=0 \\ \\ 33-56i-7b+4bi+c-33-56i+7b+4bi-c=0 \\ \\ \\ Combine \ like \ terms: \\ \\ 33-33-56i-56i-7b+7b+4bi+4bi+c-c=0 \\ \\ -112i+8bi=0 \\ \\ Isolating \ b: \\ \\ b=\frac{112i}{8i} \\ \\ \boxed{b=14}$

Finding c from (1):

$33-56i-7b+4bi+c=0 \\ \\ \\ Substituting \ b: \\ \\ 33-56i-7(14)+4(14)i+c=0 \\ \\ 33-56i-98+56i+c=0 \\ \\ -65+c=0 \\ \\ \boxed{c=65}$

<h2>Learn more:</h2>

Complex conjugate: brainly.com/question/2137496

#LearnWithBrainly

5 0

3 years ago

What is the total area of the figure below?

ki77a [65]

Answer:

Step-by-step explanation:

28×14=392, which generally already gives you the answer. But the extra area is a trapezoid so we do 4+6=10×2(height)=20, but we have to divide by two since its a trapezoid giving us 10. So 10+392=402

7 0

3 years ago

Tom bought 3 boxes of books at a yard sale. If each box had 2 books how many books did he Buy ?

Tju [1.3M]

Answer:

Step-by-step explanation:

2 books in each box.

There are three boxes

2 times 3 equals 6

3 0

3 years ago