Answer:
The coordinates of the midpoint are;
(-6.5, -3)
Step-by-step explanation:
Here, we want to get the midpoint of the line segment
To get this, we use the midpoint formula;
(x,y) = (x1 + x2)/2, (y1 + y2)/2
Thus;
(x,y) = (8 - 21)/2, (-10 + 4)/2
(x,y) = -13/2 , -6/2
(x,y) = (-6.5 , -3)
Answer:
a= m<SQR
Step-by-step explanation:
<h2>
Answer with explanation:</h2>
According to the Binomial probability distribution ,
Let x be the binomial variable .
Then the probability of getting success in x trials , is given by :
, where n is the total number of trials or the sample size and p is the probability of getting success in each trial.
As per given , we have
n = 15
Let x be the number of defective components.
Probability of getting defective components = P = 0.03
The whole batch can be accepted if there are at most two defective components. .
The probability that the whole lot is accepted :

∴The probability that the whole lot is accepted = 0.99063
For sample size n= 2500
Expected value : 
The expected value = 75
Standard deviation : 
The standard deviation = 8.53
Answer:
0 ≤ t ≤ 5.
Step-by-step explanation:
In the function
,
is the independent variable. The domain of
is the set of all values of
that this function can accept.
In this case,
is defined in a real-life context. Hence, consider the real-life constraints on the two variables. Both time and volume should be non-negative. In other words,
.
.
The first condition is an inequality about
, which is indeed the independent variable.
However, the second condition is about
, the dependent variable of this function. It has to be rewritten as a condition about
.
.
Hence, t ≤ 5.
Combine the two inequalities to obtain the domain:
0 ≤ t ≤ 5.
Given
Present investment, P = 22000
APR, r = 0.0525
compounding time = 10 years
Future amount, A
A. compounded annually
n=10*1=10
i=r=0.0525
A=P(1+i)^n
=22000(1+0.0525)^10
=36698.11
B. compounded quarterly
n=10*4=40
i=r/4=0.0525/4
A=P(1+i)^n
=22000*(1+0.0525/4)^40
=37063.29
Therefore, by compounding quarterly, she will get, at the end of 10 years investment, an additional amount of
37063.29-36698.11
=$365.18