The asymptotes are where the graph is undefined. Since: tan(x) =sin(x)/cos(x)
It is where cos(4x-π) = 0
cos(4x-π) = 0 when the inside is -π/2 , π/2 , 3π/2
4x - π = π/2
4x = π/2 + π
4x = 3π/2
x = 3π/8
4x - π = 3π/2
4x = 3π/2 + π
4x = 5π/2
x = 5π/8
This ones outside the interval (5π/8 > π/2) , try -π/2
4x - π = -π/2
4x = -π/2 + π
4x = π/2
x = π/8
Asymptotes are π/8 and 3π/8
Assuming your first equation is y = 5x+9, the equations describe lines that are coincident.
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Multiplying the second equation by -1, it becomes y = 5x+9, the same as the first equation.
A proportional relationship is described by the equation
... y = k·x
The point (x, y) = (0, 0) is <em>always</em> a solution to this equation.
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In short, if the relationship is proportional, its graph will go through the origin. If the graph does not go through the origin, the relationship is not proportional.
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Note that this is true if the domain includes the origin. You can have y = kx <em>for x > 10 </em>and the graph will <em>not</em> go through the origin because the function is <em>not defined</em> there.
The factor is x-6 since the two factors of your equation are (6x-6) and (x-6)
Answer:
a!!
Step-by-step explanation:
