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lianna [129]
3 years ago
10

To maintain an acceptable level of chlorine in your pool you add 1.4gallins of chlorine.This is 0.007℅ of the amount of water in

your pool. How many gallins of water are in your pool
Mathematics
1 answer:
Ghella [55]3 years ago
8 0

20000 gallons of water are in pool

<em><u>Solution:</u></em>

Given that To maintain an acceptable level of chlorine in your pool you add 1.4 gallons of chlorine

This is 0.007℅ of the amount of water in your pool

To find: gallons of water are in your pool

From given question,

1.4 gallons of chlorine = 0.007℅ of the amount of water in your pool

Let "x" be the amount of water in your pool

Therefore,

1.4 = 0.007 % of x

1.4 = \frac{0.007}{100} \times x\\\\1.4 = 0.00007 \times x\\\\x = \frac{1.4}{0.00007}\\\\x = 20000

Thus 20000 gallons of water are in pool

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Given g(x) = −3x + 4
Goshia [24]

Answer:

The average rate of change of <em>g</em> from <em>x</em> = <em>a</em> to<em> x</em> = <em>a</em> + <em>h</em> is -3.

Step-by-step explanation:

We are given the function:

g(x) = -3x + 4

And we want to determine its average rate of change of the function for <em>x</em> = <em>a</em> and <em>x</em> = <em>a</em> + <em>h</em>.

To determine the average rate of change, we find the slope of the function between the two points. In other words:

\displaystyle \text{Avg} = \frac{g(a + h) - g(a) }{(a + h ) - a}

Simplify:

\displaystyle \begin{aligned}  \text{Avg} &= \frac{g(a + h) - g(a) }{(a + h ) - a} \\ \\ &=\frac{(-3(a+h) + 4) - (-3a+4)}{h} \\ \\ &= \frac{(-3a -3h + 4) + (3a - 4) }{h} \\ \\ &= \frac{-3h}{h} \\ \\ &= -3\end{aligned}

In conclusion, the average rate of change of <em>g</em> from <em>x</em> = <em>a</em> to <em>x</em> = <em>a</em> + <em>h</em> is -3.

This is the expected result, as function <em>g</em> is linear, so its rate of change would be constant.

3 0
3 years ago
Triangle $ABC$ is isosceles with $AB = BC.$ If $AC = 20$ and $[ABC] = 240,$ then find the perimeter of triangle $ABC.$
gtnhenbr [62]

The perimeter of triangle ABC is 84.

5 0
3 years ago
Read 2 more answers
Pls answer 18 20 and 22 show your work
Svetlanka [38]

Answer:

18- 300

20- 1,500

22- 300

Step-by-step explanation:

You can easily find the answer like this:

18. Multiply 60 and 100 together. The hundred is from 100%. After that, divide it by 20 because of the percent. After doing this, you should get 300.

20. 360*100=36,000 36,000/24= 1,500

22. 9*100=900 900/3=300


I hope this is what you were looking for. If you need more out of this, ask me to answer it again. :)

5 0
3 years ago
A clothes shop has some special offers. T-shirts are buy one get one free and jumpers are 3 for 2. The normal price of a T-shirt
MAXImum [283]

Answer:

£17.20

Step-by-step explanation:

A clothes shop has some special offers. ?

The normal price of a T-shirt is £7.40 The normal price of a jumper is £9.80.

T-shirts are buy one get one free Jumpers are 3 for 2.

How much does it cost to get 5 jumpers and 2 T-shirts using this offer as appropriate?

The cost of 2 T-shirts since it is a buy 1 get 1 free => £7.40

The cost of 5 jumpers =

You buy 3 Jumpers ,you get 2 jumpers free => £9.80

The total cost = £7.40 + £9.80

= £17.20

4 0
2 years ago
Intravenous fluid bags are filled by an automated filling machine. Assume that the fill volumes of the bags are independent, nor
kenny6666 [7]

Answer:

a) 0.0167

b) 0

c) 5.948

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 6.16 ounces

Standard Deviation, σ = 0.08 ounces

We are given that the distribution of fill volumes of bags is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) Standard deviation of 23 bags

\displaystyle\frac{S.D}{\sqrt{23}} = \frac{0.08}{\sqrt{23}} = 0.0167

b) P( fill volume of 23 bags is below 5.95 ounces)

P(x < 5.95)

P( x < 5.96) = P( z < \displaystyle\frac{5.95 - 6.16}{0.0167}) = P(z < -12.57)

= 1 - P(z < 12.57)

Calculation the value from standard normal z table, we have,  

P(x < 5.95) = 1 - 1 = 0

c) P( fill volume of 23 bags is below 6 ounces)  = 0.001

P(x < 6)  = 0.001

P( x < 6) = P( z < \displaystyle\frac{6 - \mu}{0.0167})

Calculation the value from standard normal z table, we have,  

P( z \leq -3.09) = 0.001

\displaystyle\frac{6 - \mu}{0.0167} = -3.09\\\\\mu = 6 + (0.0167\times -3.09) = 5.948

If the mean will be 5.948 then the probability that the average of 23 bags is below 6.1 ounces is 0.001.

7 0
3 years ago
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