Question

What is the area of ∆ABC to the nearest tenth of a square meter?

Answer 1

 The answer would be: nswer: A = 587.3

Solution:
BC ^ 2 = 36 ^ 2 + 36 ^ 2 - 2 * 36 * 36 * cos (65) BC = root (1496.573466) BC = 38.68557181 Then, for the area we have: A = root (s (s-a) * (s-b) * (s-c)) s = (a + b + c) / 2 Substitute: s = (36 + 36 + 38.68557181) / 2 s = 55.34278591 A = root (55.34278591 * (55.34278591-36) * (55.34278591-36) * (55.34278591-38.68557181)) A = 587.2874463 A = 587.3 

Answer 2

The remaining side using cosine theorem is:
 BC ^ 2 = 36 ^ 2 + 36 ^ 2 - 2 * 36 * 36 * cos (65)
 BC = root (1496.573466)
 BC = 38.68557181
 Then, for the area we have:
 A = root (s (s-a) * (s-b) * (s-c))
 s = (a + b + c) / 2
 Substituting:
 s = (36 + 36 + 38.68557181) / 2
 s = 55.34278591
 A = root (55.34278591 * (55.34278591-36) * (55.34278591-36) * (55.34278591-38.68557181))
 A = 587.2874463
 Rounding off we have:
 A = 587.3
 Answer:
 A = 587.3