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andrey2020 [161]
3 years ago
12

A die is rolled twice. what is the probability of showing a 3 on both rolls?

Mathematics
1 answer:
jonny [76]3 years ago
6 0
The probability of showing a 3 on the first roll is 1/6.
The probability of showing a 3 on the second roll is 1/6.

Because the two rolls are independent events, the probability of showing a 3 on both rolls is
(1/6)*(1/6) = 1/36

Answer: 1/36

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Solve for x, given the equation Square root of x plus 9 − 4 = 1.
yuradex [85]
√x + 9 - 4 = 1
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3 years ago
If you roll two fair dice repeatedly, what is the probability that you will get a sum of 4 before you get a sum of 5 ? (a) (b) (
AlexFokin [52]

Answer:

The probability that you will get a sum of 4 before you get a sum of 5 is \frac{1}{12}

Step-by-step explanation:

Given : If you roll two fair dice repeatedly.

To find : What is the probability that you will get a sum of 4 before you get a sum of 5 ?

Solution :

When two dice are rolled the outcomes are

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

Total number of outcomes = 36

Favorable outcome get a sum of 4 before you get a sum of 5 is (1,3) ,(2,2) and (3,1) = 3

The probability that you will get a sum of 4 before you get a sum of 5 is

P=\frac{3}{36}

P=\frac{1}{12}

Therefore, The probability that you will get a sum of 4 before you get a sum of 5 is \frac{1}{12}

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