Question

c%7B125%7D%7B3%7D%20" id="TexFormula1" title=" \frac{3}{4} x + \frac{5}{6} = 5x - \frac{125}{3} " alt=" \frac{3}{4} x + \frac{5}{6} = 5x - \frac{125}{3} " align="absmiddle" class="latex-formula">
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Answer 1

Answer:

nos   agoi o se

Step-by-step explanation:

Answer 2

Answer:

$\boxed{\bold{\huge{\boxed{x = 10}}}}$

Step-by-step explanation:

=> $\sf \frac{3}{4} x + \frac{5}{6} = 5x - \frac{125}{3}$

Combining like terms

=> $\sf \frac{3x}{4} - 5x = -\frac{125}{3} - \frac{5}{6}$

Taking LCM to make the denominator same

=> $\sf \large{\frac{3x-20x}{4} = \frac{-250-5}{6} }$

=> $\sf \frac{-17x }{4} = \frac{-255}{6}$

=> $\sf \frac{17x }{4} = \frac{255}{6}$

Cross Multiplying

=> $\sf 17x * 6 = 4 * 255$

=> $\sf 102x = 1020$

Dividing both sides by 102

=> x = 10