<img src="https://tex.z-dn.net/?f=%20%20%5Cfrac%7B3%7D%7B4%7D%20x%20%2B%20%20%5Cfrac%7B5%7D%7B6%7D%20%20%3D%205x%20-%20%20%5Cfra

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3 years ago

c%7B125%7D%7B3%7D%20" id="TexFormula1" title=" \frac{3}{4} x + \frac{5}{6} = 5x - \frac{125}{3} " alt=" \frac{3}{4} x + \frac{5}{6} = 5x - \frac{125}{3} " align="absmiddle" class="latex-formula">

Mathematics

2 answers:

jonny [76]3 years ago

6 0

Answer:

nos agoi o se

Step-by-step explanation:

sweet [91]3 years ago

4 0

Answer:

$\boxed{\bold{\huge{\boxed{x = 10}}}}$

Step-by-step explanation:

=> $\sf \frac{3}{4} x + \frac{5}{6} = 5x - \frac{125}{3}$

Combining like terms

=> $\sf \frac{3x}{4} - 5x = -\frac{125}{3} - \frac{5}{6}$

Taking LCM to make the denominator same

=> $\sf \large{\frac{3x-20x}{4} = \frac{-250-5}{6} }$

=> $\sf \frac{-17x }{4} = \frac{-255}{6}$

=> $\sf \frac{17x }{4} = \frac{255}{6}$

Cross Multiplying

=> $\sf 17x * 6 = 4 * 255$

=> $\sf 102x = 1020$

Dividing both sides by 102

=> x = 10

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Arrange the numbers in decreasing order of their values.

FinnZ [79.3K]

Answer:

The numbers in decreasing order of their values are:

$\cfrac{19}{3}>\sqrt{37}>6.08171...>6.012$

Step-by-step explanation:

Before actually comparing, we need to write all of those numbers in decimal form, that will be the only way to actually tell which one is bigger since you are already given numbers in decimal form.

Converting numbers in decimal form.

The first number we are given is $\sqrt{37}$ , we know it is a bit higher than 6, since the square root of 36 is 6, so using a calculator we get