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Marizza181 [45]
3 years ago
7

Directions: Use a proportion to solve the problem.

Mathematics
1 answer:
spin [16.1K]3 years ago
5 0
So, since she weights 6 times more on earth, say for every lb on the moon  is 6lbs on earth then.

now, if 1lb on the moon is 6lbs on earth, how much is 90 earth lbs on the moon?

\bf \begin{array}{ccll}
moon&earth\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
1&6\\
m&90
\end{array}\implies \cfrac{1}{m}=\cfrac{6}{90}\implies \cfrac{1\cdot 90}{6}=m
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Svetach [21]

Answer:

what type of cereal

Step-by-step explanation:

6 0
3 years ago
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Which of the following equations shows how substitution can be used to solve
maxonik [38]

Answer:  Choice B)

2x+5(2x+3) = 3

============================================

Reasoning:

We start with the second equation 2x+5y = 3

Since y = 2x+3 from the first equation, we can replace every copy of y with (2x+3). This replacement is valid because y and 2x+3 are the same.

So that's how we go from 2x+5y = 3 to 2x+5(2x+3) = 3

This replacement is done to get rid of the y variable, and it allows us to solve for x later on.

3 0
3 years ago
Solve for x. 8(9x-4)-2=3+2
gavmur [86]
So first you have to move the -2 over to the opposite side.
8(9x-4)=3+2+2
Then you can simplify the right side 
8(9x-4)=7
Then you distribute
8*9x=72x
8*-4=-32
so now you have...
72x-32=7
Then you move the 37 over
72x=39
Then you divide by 72 to isolate x
x=39/72 or x= 13/24 or <span>x=0.54167</span>
6 0
3 years ago
The probability of passing the math class of Professor Jones is 64%, the probability of passing Professor Smith's physics class
alexgriva [62]

Answer:

The probability of using one or the other is 36%

Step-by-step explanation:

For solving this problem it is easy if we see it in a ven diagram, for this first we are going to name the initial conditions with some variables:

Probability of passing Professor Jones math class = 64% =0,64

P(J) = 0.64

Probabiliry of passing Professor Smith's physics class = 32% =0.32

P(S) = 0.32

Probability of passing both is = 30% = 0.30

P(JnS) = 0.30 (Is is an intersection so it is in the middle of the ven diagram

We need to know which is the probability of pasing one or the other for this we need to take out the probability of passing both for this we have to add the probability of passing  Professor Jones math class with the probabiliry of passing Professor Smith's physics class and substract the probability of passing both for each one:

P(JuS) = (P(J) - P(JnS)) + (P(S) - P(JnS)) = (0.64 - 0.30) + (0.32 - 0.30) = 0.34 + 0.02 = 0.36 = 36%

If you check the ven diagram you can see that if we add all what is in red we will have the probability of passing Professor Jones math class and if we add all what is in blue we wiill have the probability of passing Professor Smith's physics class, and if we add just what is in each corner we will get the same value that is the probabilty of passsing one or the other.

5 0
3 years ago
How long will it take to earn $568.75 in interest if $2500 is invested at a 6.5% annual interest rate
zheka24 [161]
3.5 years (so 4 years)
2500×0.065 (this gets the amout earned per year) =162.5
568.75÷162.5 (how many years to get the desired amount) =3.5
8 0
3 years ago
Read 2 more answers
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