Area of the square is 144m.
Area of the circle is 113.1m.
Subtract A of circle from A of Square which equals 30.9meters. That is your answer.
If you want I can teach you step by step just comment if you want me to...
Let Ch and C denote the events of a student receiving an A in <u>ch</u>emistry or <u>c</u>alculus, respectively. We're given that
P(Ch) = 88/520
P(C) = 76/520
P(Ch and C) = 31/520
and we want to find P(Ch or C).
Using the inclusion/exclusion principle, we have
P(Ch or C) = P(Ch) + P(C) - P(Ch and C)
P(Ch or C) = 88/520 + 76/520 - 31/520
P(Ch or C) = 133/520
Answer:
x=3
Step-by-step explanation:
Right triangle so you can use pythagorean theorem
a squared + b squared = c squared
b=x
14^2 + b^2= 17^2
14+b=17
b=3
6 is the mode since it appears the most, 3 times
Answer:
use the formula sn= n(a1+an)/2
Step-by-step explanation:
2982=28(228+an)/2
5964=28(228+an)
5964/28=228+an
213=228+an
an=-15(last term)
to find difference use formula
an = a+(n-1)d
-15=228+(28-1)d
-243=27d
d=-243/27
d=-9
arithmetic sequence can be found be keep on subtracting 9 from 228
hence the arithmetic sequence is
228, 219, 210, 201, 192, 183, 174........-15
