The point on the curve is (–4, 140)
Solution:
Given 
and slope is –67.
slope = –67
– – – – (1)
Now calculate 
for the given curve .
Using differential rule:
– – – – (2)
Equate (1) and (2).
⇒ x = –4
Substitute x = –4 in y.
⇒ 
⇒ 
⇒ y = 140
Hence, the point on the curve given is (–4, 140).
Answer:
the answer is 28
Step-by-step explanation:
2×4+4+5
8+20
28
Answer:
see explanation
Step-by-step explanation:
Given a quadratic function in standard form y = ax² + bx + c ( a ≠ 0)
• If a > 0 the the graph has a minimum value ∪
• If a < 0 then the graph has a maximum value ∩
Thus y = - 3x² + 1 ← has a maximum value and
y = x² ← has a minimum value
Hello :
<span>y - 4 = (x+1)²
h = -1 and k=4
the vertex is : A(-1 ; 4)</span>
Answer:
equation: 2.75 g/cm^3 * 1 m *3 m* (100 cm/1 m)^2 *4 cm * (1 kg/1000 g)
Step-by-step explanation:
countertop mass, m =?
density, ρ = 2.75 g/cm^3
wide, w = 1 m
long, l = 3 m
thick, t = 4 cm
countertop volume, V = w*l*t = 1 m *3 m*4 cm* (100 cm/1 m)^2
Isolating mass from density definition gives
ρ = m/V
m = ρ*V
m = 2.75 g/cm^3 * 1 m *3 m* (100 cm/1 m)^2 *4 cm * (1 kg/1000 g)
