Answer:
hcf:3x^3-6x^2+y^2-3x+54
lcm:2(x+3)(x^2-3x+9)(x^3-3x^2+9)(y^2-3x+9)
The standard form of the quadratic function f(x) = -3x^2 + 6x - 2 is f(x) = -3x^2 + 6x - 2
<h3>How to represent the
quadratic function in standard form?</h3>
The quadratic function is given as
f(x) = -3x^2 + 6x - 2
The standard form of a quadratic function is represented as:
f(x) = ax^2 + bx + c
When both equations are compared, we can see that the function f(x) = -3x^2 + 6x - 2 is already in standard form
Where
a = -3
b = 6
c = -2
Hence, the standard form of the quadratic function f(x) = -3x^2 + 6x - 2 is f(x) = -3x^2 + 6x - 2
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Answer:
37 is prime number
Step-by-step explanation:
To prove whether a number is a prime number, first try dividing it by 2, and see if you get a whole number. If you do, it can't be a prime number. If you don't get a whole number, next try dividing it by prime numbers: 3, 5, 7, 11 (9 is divisible by 3) and so on, always dividing by a prime number
Answer:
x<-1
Step-by-step explanation:
I think and hope it helps
Answer:
<h2>
AB=8.4 inches</h2><h2>
AC=13.05 inches</h2>
Solution,
Hope this helps...
Good luck on your assignment..
