Ask question

Ask question

All categories

3 years ago

13

The volume of a cylinder is 2,200 pie cubic inches. The diameter of the circular base is 10 inches. What is the height of the cy

linder

1 answer:

Elis [28]3 years ago

5 0

Answer:

Step-by-step explanation:

H = V/ pie r^2

H = $\frac{2200pie}{Pie 5^2}$

R= 5 because the radius is half the diameter

Pies cancel out leaving you with:

H = 2200/5^2

H = 2200/25

H = 88

Hope this helps :)

You might be interested in

Which is the solution to the inequality?<br> 1/4 + x <5/6

Bumek [7]

Answer:

install app photomath ;D

5 0

3 years ago

Find the slope of the line y = -7/6x - 8/3.

Nezavi [6.7K]

Hello!

This equation is written in slope-intercept form.

Slope-intercept form is y = mx + b, where m is the slope and y is the y-intercept.

Since the coefficient -7/6 is multiplied with x, the slope (or m) has to equal to -7/6.

Therefore, the slope of the line is -7/6.

8 0

3 years ago

Use Stokes' Theorem to evaluate C F · dr F(x, y, z) = xyi + yzj + zxk, C is the boundary of the part of the paraboloid z = 1 − x

Serggg [28]

I assume $C$ has counterclockwise orientation when viewed from above.

By Stokes' theorem,

$\displaystyle\int_C\vec F\cdot\mathrm d\vec r=\iint_S(\nabla\times\vec F)\cdot\mathrm d\vec S$

so we first compute the curl:

$\vec F(x,y,z)=xy\,\vec\imath+yz\,\vec\jmath+xz\,\vec k$

$\implies\nabla\times\vec F(x,y,z)=-y\,\vec\imath-z\,\vec\jmath-x\,\vec k$

Then parameterize $S$ by

$\vec r(u,v)=\cos u\sin v\,\vec\imath+\sin u\sin v\,\vec\jmath+\cos^2v\,\vec k$

where the $z$ -component is obtained from

$1-(\cos u\sin v)^2-(\sin u\sin v)^2=1-\sin^2v=\cos^2v$

with $0\le u\le\dfrac\pi2$ and $0\le v\le\dfrac\pi2$ .

Take the normal vector to $S$ to be

$\vec r_v\times\vec r_u=2\cos u\cos v\sin^2v\,\vec\imath+\sin u\sin v\sin(2v)\,\vec\jmath+\cos v\sin v\,\vec k$

Then the line integral is equal in value to the surface integral,

$\displaystyle\iint_S(\nabla\times\vec F)\cdot\mathrm d\vec S$

$=\displaystyle\int_0^{\pi/2}\int_0^{\pi/2}(-\sin u\sin v\,\vec\imath-\cos^2v\,\vec\jmath-\cos u\sin v\,\vec k)\cdot(\vec r_v\times\vec r_u)\,\mathrm du\,\mathrm dv$

$=\displaystyle-\int_0^{\pi/2}\int_0^{\pi/2}\cos v\sin^2v(\cos u+2\cos^2v\sin u+\sin(2u)\sin v)\,\mathrm du\,\mathrm dv=\boxed{-\frac{17}{20}}$

6 0

3 years ago

An airplane leaves New York to fly to Los Angeles. It travels 3,850 km in 5.5 hours. What is the velocity of the airplane?

Ilya [14]

Answer:

C. 700 km/hour

Step-by-step explanation:

7 0

3 years ago

How do I send pictures?

kompoz [17]

Step-by-step explanation:

By pressing the button that looks like this

4 0

3 years ago

Read 2 more answers