Answer:
9
Step-by-step explanation:
If you want the number to be divisible by three make sure the sum of all the numbers are divisible by three. Add all the numbers you have to see what they make.
3+4+2+8+4=21
So we just need to find the greatest number we can add to that to have it remain divisible by three. A number divisible by three is 30, and we can add 9 to 21 to make 30. Of course, there are other numbers we could add, but nine is the largest one-digit number that would work. Other smaller numbers include 3 and 6.
3+4+2+8+4+9=30
Now we check to see if our number is divisible by three
342984÷3 = 114328
114328 is a whole number so we know it's divisible.
Answer:
The person solving the problem first subtracted 6 from 15. Since the cube root is next to the six, the problem should be read as ![15-6(\sqrt[3]{\frac{-1000}{27} } )](https://tex.z-dn.net/?f=15-6%28%5Csqrt%5B3%5D%7B%5Cfrac%7B-1000%7D%7B27%7D%20%7D%20%29)
rather than ![(15-6)(\sqrt[3]{\frac{-1000}{27} } )](https://tex.z-dn.net/?f=%2815-6%29%28%5Csqrt%5B3%5D%7B%5Cfrac%7B-1000%7D%7B27%7D%20%7D%20%29)
.
- To solve it correctly, first find the cube root of -1000/27: <u>-10/3</u>
- Next, multiply by 6: -20
- Finally, subtract from 15: 35
please lmk if anything is wrong with my answer, hope this helps :)
Answer:
=288
Step-by-step explanation:
(4yz)-3(x)
(4(4)(2))-3(-3)
(4x8)x9
32x9
288
