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3 years ago

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Another parking lot with three sections has 80 cars in it. Is it possible for ratio of the number of cars in the first section t

o the number of cars in the second section to the number of cars in the third section to be 1:2 :3? Explain why or why not.

1 answer:

shusha [124]3 years ago

4 0

Yes. 80:160:240 will equal to 1:2:3

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4 to the 8th power divided by 4 to the 5th power

Natasha2012 [34]

Alright, 4 to the 8th power is 4x4x4x4x4x4x4x4 which ends up as 65,536.

4 to the 5th power is the same thing but with 5 4's and that is 1,024.

All you need to do now is 65,536/1,024 = 64.

Solved! :D

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3 years ago

Nancy is a telemarketer who calls 96 people each day. How many people will she call in a 5-day workweek?

ss7ja [257]

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3 years ago

Given the quadratic equation <img src="https://tex.z-dn.net/?f=y%20%3D%202%28x%20-1%29%5E%7B2%7D%20%2B%208" id="TexFormula1" tit

Sunny_sXe [5.5K]

Answer:

Part 1) "a" value is $2$

Part 2) The vertex is the point $(1,8)$

Part 3) The equation of the axis of symmetry is $x=1$

Part 4) The vertex is a minimum

Part 5) The quadratic equation in standard form is $y=2x^{2}-4x+10$

Step-by-step explanation:

we know that

The equation of a vertical parabola into vertex form is equal to

$y=a(x-h)^{2}+k$

where

(h,k) is the vertex of the parabola

if a > 0 then the parabola open upward (vertex is a minimum)

if a < 0 then the parabola open downward (vertex is a maximum)

The equation of the axis of symmetry of a vertical parabola is equal to the x-coordinate of the vertex

so

$x=h$

In this problem we have

$y=2(x-1)^{2}+8$ -----> this is the equation in vertex form of a vertical parabola

The value of $a=2$

so

a>0 then the parabola open upward (vertex is a minimum)

The vertex is the point $(1,8)$

so

$(h,k)=(1,8)$

The equation of the axis of symmetry is $x=1$

The equation of a vertical parabola in standard form is equal to

$y=ax^{2}+bx+c$

Convert vertex form in standard form

$y=2(x-1)^{2}+8$

$y=2(x^{2}-2x+1)+8$

$y=2x^{2}-4x+2+8$

$y=2x^{2}-4x+10$

see the attached figure to better understand the problem

7 0

3 years ago

A rectangular park of length 60 m breadth 50 m encloses w volleyball court of length 18 m and breadth 10 m. Find the area of the

Zanzabum

Given

A rectangular park of length 60 m breadth 50 m encloses with volleyball court of length 18 m and breadth 10 m.

To find:

The area of the park excluding the court at the rate of Rs 110 per square meter.

Solution:

Area of a rectangle is:

$Area=length \times breadth$

Area of whole park is:

$A_1=60 \times 50$

$A_1=3000$

Area of volleyball court is:

$A_2=18 \times 10$

$A_2=180$

Now, the area of the park excluding the court is:

$A=A_1-A_2$

$A=3000-180$

$A=2820$

Therefore, the area of the park excluding the court is 2820 square meter.

4 0

3 years ago

Tonya is making a scale model of a monument that is 160 feet tall. If she uses a scale of 4 in. = 5 ft., how tall should she mak

olasank [31]

Answer:

<u>It should be 128 inches or 10.67 feet tall</u>

Step-by-step explanation:

Real size of the monument = 160 feet tall

Scale used by Tonya = 4 inches equal to 5 feet

Scale model of the monument = Real size of the monument / Scale used

Proportion between real monument and scale model = 160 / 5 = 32

It means that the proportion between the real monument and the scale model is 32

Scale model height = Proportion * scale used

Scale model height = 32 * 4

<u>Scale model height = 128 inches</u>

<u>Scale model height = 128/12 = 10.67 feet (12 inches = 1 feet)</u>

4 0

3 years ago