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Olin [163]
3 years ago
12

Write an equation for the line that passes through (2,-5) and is parallel to 3x+4y=8

Mathematics
1 answer:
mote1985 [20]3 years ago
3 0
<span>3x+4y=8
4y = -3x + 8; slope = -3
</span><span>parallel lines, slope is the same so slope = -3
</span><span>passes through (2,-5) 
y  = mx + b
b = y - mx
b = -5 - (-3)(2)
b = -5 + 6
b = 1

equation
y = -3x +1

hope it helps</span>
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Answer:

7y +8 is the answer for the question

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a company that manufactures bicycles has a fixed cost of $80,000. it costs $100 to produce each bicycle. the total cost for the
frez [133]

C(x) = 80000 + 100x is the total cost as function of number of cycles produced

C(90) = 89000 and it costs $ 89000 to produce 90 bicycles

<em><u>Solution:</u></em>

Given that, company that manufactures bicycles has a fixed cost of $80,000

Fixed cost = $ 80,000

Let x be the number of cycles produced

Let C(x) be the total cost as function of number of cycles produced

It costs $100 to produce each bicycle

Variable cost = 100 x number of cycles produced

variable cost = 100x

The total cost for the company is the sum of its fixed cost and variable costs

total cost = fixed cost + variable cost

C(x) = 80000 + 100x

Thus total cost as function of "x" is found

<em><u>Find and interpret C(90)</u></em>

Substitute x = 90 in C(x)

C(90) = 80000 + 100(90)

C(90) = 80000 + 9000

C(90) = 89000

Thus it costs $ 89000 to produce 90 bicycles

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A small business owner estimates his mean daily profit as $970 with a standard deviation of $129. His shop is open 102 days a ye
Katena32 [7]

Answer:

The probability that the shopkeeper's annual profit will not exceed $100,000 is 0.2090.

Step-by-step explanation:

According to the Central Limit Theorem if we have a population with mean <em>μ</em> and standard deviation <em>σ</em> and we select appropriately huge random samples (<em>n</em> ≥ 30) from the population with replacement, then the distribution of the sum of values of <em>X</em>, i.e ∑<em>X</em>, will be approximately normally distributed.  

Then, the mean of the distribution of the sum of values of X is given by,  

 \mu_{x}=n\mu

And the standard deviation of the distribution of the sum of values of X is given by,  

 \sigma_{x}=\sqrt{n}\sigma

The information provided is:

<em>μ</em> = $970

<em>σ</em> = $129

<em>n</em> = 102

Since the sample size is quite large, i.e. <em>n</em> = 102 > 30, the Central Limit Theorem can be used to approximate the distribution of the shopkeeper's annual profit.

Then,

\sum X\sim N(\mu_{x}=98940,\ \sigma_{x}=1302.84)

Compute the probability that the shopkeeper's annual profit will not exceed $100,000 as follows:

P (\sum X \leq  100,000) =P(\frac{\sum X-\mu_{x}}{\sigma_{x}}

                              =P(Z

*Use a <em>z</em>-table for the probability.

Thus, the probability that the shopkeeper's annual profit will not exceed $100,000 is 0.2090.

6 0
3 years ago
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