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4 years ago

Write an equation for the line that passes through (2,-5) and is parallel to 3x+4y=8

1 answer:

mote1985 [20]4 years ago

3 0

3x+4y=8
4y = -3x + 8; slope = -3
parallel lines, slope is the same so slope = -3
passes through (2,-5)
y = mx + b
b = y - mx
b = -5 - (-3)(2)
b = -5 + 6
b = 1

equation
y = -3x +1

hope it helps

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Chem deposited $115.00 in a savings account. Each week thereafter, he

Yanka [14]

Answer:

Part a) $y=35x+115$

Part b) $\$1,165$

Step-by-step explanation:

Part a)

Let

x -----> the number of weeks

y ----> the total amount Chem has deposited in a saving account

we know that

The equation of a line in slope intercept form is

$y=mx+b$

where

m is the rate or slope of the linear equation

b is the y-intercept of the linear equation or initial value (value of y when the value of x is equal to zero)

In this problem we have that

The rate or slope is equal to

$m=35\frac{\$}{week}$ -----> amount deposited by Chem each week

The y-intercept or initial value is

$b=\$115$ ----> amount deposited originally in the saving account

substitute the values

$y=35x+115$

Part b) How much has Chem deposited 30 weeks after his initial deposit?

For x=30 weeks

substitute in the equation

$y=35(30)+115$

$y=\$1,165$

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3 years ago

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sattari [20]

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4 years ago

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Mekhanik [1.2K]

Answer:

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Step-by-step explanation:

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3 years ago

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algol13

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