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2 years ago

7

Three friends go to a book fair. Allen spends $2.40. Maria spends 4 times as much as Allen. Akio spends $3.45 less than Maria. H

ow much does Akio spend? Akio spends $ at the book fair.

1 answer:

kiruha [24]2 years ago

8 0

Akio spends $6.15 at the book fair.

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What is the value of x

Kisachek [45]

Answer:

$x=98$

Step-by-step explanation:

Angles in a triangle add up to 180°

$180-45-53$

$=82$

Angles in a straight line add up to 180°

$180-82$

$=98$

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3 years ago

Read 2 more answers

If an experimenter sets equal to .01, then she is defining a "statistically rare" event as an event occurring more than one time

Fynjy0 [20]

Answer:

The correct answer is an event occurring one or fewer times in 100 times if the null hypothesis is true.

Step-by-step explanation:

For a statistically rare event, its probability is relatively small and the event is very unlikely to occur. Therefore, if an experimental sets equal to 0.01 which is statistically rare, then we can interpret this mathematically as:

p(event) = 0.01 = 1/100

where p(event) is the probability of the event.

In addition, statistically, null hypothesis signifies no major difference between the specified parameters, and any obvious difference that might occur as a result of experimental error. Thus, it can be concluded that the event is occurring one or fewer times in 100 times if the null hypothesis is true.

3 0

3 years ago

Please help me i need help bad .

Hoochie [10]

Answer:

I think the answer is D. 4

4 0

3 years ago

Given the sequence 1/2 ; 4 ; 1/4 ; 7 ; 1/8 ; 10;.. calculate the sum of 50 terms

miv72 [106K]

<u>Hint </u><u>:</u><u>-</u>

Break the given sequence into two parts .
Notice the terms at gap of one term beginning from the first term .They are like $\dfrac{1}{2},\dfrac{1}{4},\dfrac{1}{8}$ . Next term is obtained by multiplying half to the previous term .
Notice the terms beginning from 2nd term , $4,7,10,13$ . Next term is obtained by adding 3 to the previous term .

<u>Solution</u><u> </u><u>:</u><u>-</u><u> </u>

We need to find out the sum of 50 terms of the given sequence . After splitting the given sequence ,

$\implies S_1 = \dfrac{1}{2},\dfrac{1}{4},\dfrac{1}{8}$ .

We can see that this is in <u>Geometric</u><u> </u><u>Progression </u> where 1/2 is the common ratio . Calculating the sum of 25 terms , we have ,

$\implies S_1 = a\dfrac{1-r^n}{1-r} \\\\\implies S_1 = \dfrac{1}{2}\left[ \dfrac{1-\bigg(\dfrac{1}{2}\bigg)^{25}}{1-\dfrac{1}{2}}\right]$

Notice the term $\dfrac{1}{2^{25}}$ will be too small , so we can neglect it and take its approximation as 0 .

$\implies S_1\approx \cancel{ \dfrac{1}{2} } \left[ \dfrac{1-0}{\cancel{\dfrac{1}{2} }}\right]$

$\\\implies \boxed{ S_1 \approx 1 }$

$\rule{200}2$

Now the second sequence is in Arithmetic Progression , with common difference = 3 .

$\implies S_2=\dfrac{n}{2}[2a + (n-1)d]$

Substitute ,

$\implies S_2=\dfrac{25}{2}[2(4) + (25-1)3] =\boxed{ 908}$

Hence sum = 908 + 1 = 909

7 0

2 years ago

The thickness of a flange on an aircraft component is uniformly distributed between 0.95 and 1.05 millimeters. (a) Determine the

maxonik [38]

Answer:

a) 0.5 = 50% of flanges exceed 1 millimeter.

b) A thickness of 0.96 millimeters is exceeded by 90% of the flanges

Step-by-step explanation:

A distribution is called uniform if each outcome has the same probability of happening.

The uniform distributon has two bounds, a and b, and the probability of finding a value higher than x is given by:

$P(X > x) = \frac{b - x}{b - a}$

The thickness of a flange on an aircraft component is uniformly distributed between 0.95 and 1.05 millimeters.

This means that $a = 0.95, b = 1.05$

(a) Determine the proportion of flanges that exceeds 1.00 millimeters.

$P(X > 1) = \frac{1.05 - 1}{1.05 - 0.95} = \frac{0.05}{0.1} = 0.5$

0.5 = 50% of flanges exceed 1 millimeter.

(b) What thickness is exceeded by 90% of the flanges?

This is x for which:

$P(X > x) = 0.9$

So

$\frac{1.05 - x}{1.05 - 0.95} = 0.9$

$1.05 - x = 0.9*0.1$

$x = 1.05 - 0.9*0.1$

$x = 0.96$

A thickness of 0.96 millimeters is exceeded by 90% of the flanges

4 0

2 years ago