Which of the following is not a step in solving 5x – 2(3x + 5) = 32? A. –x = 42 B. –1x = 42 C. –x + 10 = 32 D. 5x – 6x – 10 = 32
2 answers:
In order to figure this our we need to solve the problem:
<span>5x – 2(3x + 5) = 32
Start by distributing the 2:
</span>
<span>
Now we have:
</span>
(Option D is seen here)
<span>
Combine like terms:
</span>
<span>
Now we have:
</span>
(Option C is seen here)
<span>
Add 10 to both sides:
</span>tex]-x-10+10=32+10 [/tex]
Now we have :
(This is seen in both option A and B)
You've made a mistake in typing your options. All of the options you've given are involved. <span />
<span>5x – 2(3x + 5) = 32
Start by distributing the 2:
</span>
<span>
Now we have:
</span>
<span>
Combine like terms:
</span>
<span>
Now we have:
</span>
<span>
Add 10 to both sides:
</span>tex]-x-10+10=32+10 [/tex]
Now we have :
You've made a mistake in typing your options. All of the options you've given are involved. <span />
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Part A:
From the central limit theorem, since the number of samples is large enough (up to 30), the mean of the the mean of the average number of moths in 30 traps is 0.6.
Part B:
The standard deviation is given by the population deviation divided by the square root of the sample size.
Part C:
The probability that an approximately normally distributed data with a mean, μ, and the standard deviation, σ, with a sample size of n is greater than a number, x, given by
Thus, given that the mean is 0.6 and the standard deviation is 0.4, the probability that <span>the average number of moths in 30 traps is greater than 0.7</span> given by:
From the central limit theorem, since the number of samples is large enough (up to 30), the mean of the the mean of the average number of moths in 30 traps is 0.6.
Part B:
The standard deviation is given by the population deviation divided by the square root of the sample size.
Part C:
The probability that an approximately normally distributed data with a mean, μ, and the standard deviation, σ, with a sample size of n is greater than a number, x, given by
Thus, given that the mean is 0.6 and the standard deviation is 0.4, the probability that <span>the average number of moths in 30 traps is greater than 0.7</span> given by:
Answer:
4k-6
Step-by-step explanation: