Look at the picture.
1)|AM| = |MB| = x
|AN| = |NC| = y
|BC| = 2y - 2x = 2(y - x)
|MN| = y - x
Therefore |BC| = 2|MN|
2)|AM| = |MB| = x
|AN| = |NC| = y
|BC| = 2y - 2x = 2(y - x)
|MN| = y - x
Therefore |BC| = 2|MN|
Answer:
Cost of 500 g of standard pack = € 7.50
Cost of 1 g of standard pack = 7.50/500
Cost of 100 g of standard pack = 7.50/500 ×100
= 7.50/5
= € 1.50
Hope it helps uh dear
Answer:
Step-by-step explanation:
the first one
Answer:
Range = (237100, 292900)
Step-by-step explanation:
Using Chebyshevs Inequality:






Thus, 88.9% of the population is within 3 standard deviation of the mean with the Range = μ ± kσ
where;
μ = 265000
σ = 9300
Range = 265000 ± 3(9300)
Range = 265000 ± 27900
Range = (265000 - 27900, 265000 + 27900)
Range = (237100, 292900)