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4 years ago

Identify the correct lewis structure for the following ionic compound. SrO

2 answers:

8 0

For the problem presented, the correct Lewis structure for SrO is [Sr]^+2 + [O]^-2. I am hoping that this answer has satisfied your query about this specific question. Also, if you have further questions, please don’t hesitate to ask away.

meriva4 years ago

6 0

The ionic compund Sro appers to be in group 2, it has a valence electrons and oxygen appears in group 16 with 16 electrons which means it can obtain 2 electrons to achieve a full valence shell. so the answer to your question is Sr^2 and Oxyge^-2

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is this atom more likely to gain or lose electrons? explain how you can tell in at least two sentences

JulijaS [17]

Answer:

Explanation:

the element is sulphur so it gains electrons, since it is not a metal

6 0

3 years ago

Read 2 more answers

What is the pH of a buffer solution upon mixing 15.0 mL of 0.40 M HCl and 20.0 mL of 0.50 M NH? Kb (NH3) = 1.8 x 10 E. 7.00 A. 9

vladimir2022 [97]

Answer: The pH of resulting solution is 9.08

Explanation:

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in mL)}}$ ........(1)

For HCl:

Molarity of HCl = 0.40 M

Volume of solution = 15.0 mL

Putting values in equation 1, we get:

$0.40M=\frac{\text{Moles of HCl}\times 1000}{15.0mL}\\\\\text{Moles of HCl}=0.006mol$

For ammonia:

Molarity of ammonia = 0.50 M

Volume of solution = 20.0 mL

Putting values in equation 1, we get:

$0.50M=\frac{\text{Moles of ammonia}\times 1000}{20.0mL}\\\\\text{Moles of ammonia}=0.01mol$

The chemical reaction for hydrochloric acid and ammonia follows the equation:

$HCl+NH_3\rightarrow NH_4Cl$

Initial: 0.006 0.01

Final: - 0.004 0.006

Volume of solution = 15.0 + 20.0 = 35.0 mL = 0.035 L (Conversion factor: 1 L = 1000 mL)

To calculate the pOH of basic buffer, we use the equation given by Henderson Hasselbalch:

$pOH=pK_b+\log(\frac{[salt]}{[base]})$

$pOH=pK_b+\log(\frac{[NH_4Cl]}{[NH_3]})$

We are given:

$pK_b$ = negative logarithm of base dissociation constant of ammonia = $-\log (1.8\times 10^{-5})=4.74$

$[NH_4Cl]=\frac{0.006}{0.035}$

$[NH_3]=\frac{0.004}{0.035}$

pOH = ?

Putting values in above equation, we get:

$pOH=4.74+\log(\frac{0.006/0.035}{0.004/0.035})\\\\pOH=4.92$

To calculate pH of the solution, we use the equation:

$pH+pOH=14\\pH=14-4.92=9.08$

Hence, the pH of the solution is 9.08

3 0

4 years ago

Aleksandr-060686 [28]

Answer:

Hello There!!

Explanation:

I believe the answer is how fast the molecules are vibrating.

hope this helps,have a great day!!

~Pinky~

8 0

3 years ago

Write one word for the following short form of an element

ra1l [238]

Answer:

symbol?

Explanation:

6 0

3 years ago

How many pounds of carbon dioxide are emitted of 400 liter pls i need asap

Nookie1986 [14]

884 pounds of carbon dioxide are emitted in 400 litres.

What is a pound?

The pound is defined as the basic unit for weight in the Foot Pound Second (F.P.S) system and is equal to 16 ounces.

To convert a litre measurement to a pound measurement, multiply the volume by 2.204623 times the density of the ingredient or material. Thus, the volume in pounds is equal to the litres multiplied by 2.204623 times the density of the ingredient or material.

One litre of water weighs approximately 2.21 pounds.

So 400 liter = 400 liter x 2.21 pounds

= 884 pounds

Hence, 884 pounds of carbon dioxide are emitted in 400 litres.

Learn more about the pounds here:

brainly.com/question/4262393

#SPJ1

4 0

2 years ago