Answer:
0.313L
Explanation:
0.25Mx1.00L=0.80Mx V2
so, 0.25x1.00/0.80=0.313L
MO Diagram of C₂⁻ is shown below,
Bond order is calculated as,
Bond Order = [# of e⁻s in BMO]-[#of e⁻s in ABMO] / 2
Where,
BMO = Bonding Molecular Orbital
ABMO = Anti-Bonding Molecular Orbital
Putting values,
Bond Order = [9]-[4] / 2
Bond Order = 5 / 2
Bond Order = 2.5
Work as the rest are forms of electricity
The correct answer is the degree of exactness in a measurement