Answer:
Original claim is 
Opposite claim is 
Null and alternative hypotheses:


Significance level: 0.01
Test statistic:
We can use TI-84 calculator to find the test statistic and P-value. The steps are as follows:
Press STAT and the scroll right to TESTS
Scroll down to 2-SampTTest... and scroll to stats.
Enter below information.







Pooled: Yes
Calculate.
The output is in the attachment.
Therefore, the test statistic is:

P-value: 0.4412
Reject or fail to reject: Fail to reject
Final Conclusion: Since the p-value is greater than the significance level, we, therefore, fail to reject the null hypothesis and conclude that the there is sufficient evidence to support the claim that the samples are from populations with the same mean.
Answer:
(6,—6)
Step-by-step explanation:
Draw the points on a table. The answer will be (6,—6)
Answer:
<h2>14mph</h2>
Step-by-step explanation:
Given the gas mileage for a certain vehicle modeled by the equation m=−0.05x²+3.5x−49 where x is the speed of the vehicle in mph. In order to determine the speed(s) at which the car gets 9 mpg, we will substitute the value of m = 9 into the modeled equation and calculate x as shown;
m = −0.05x²+3.5x−49
when m= 9
9 = −0.05x²+3.5x−49
−0.05x²+3.5x−49 = 9
0.05x²-3.5x+49 = -9
Multiplying through by 100
5x²+350x−4900 = 900
Dividing through by 5;
x²+70x−980 = 180
x²+70x−980 - 180 = 0
x²+70x−1160 = 0
Using the general formula to get x;
a = 1, b = 70, c = -1160
x = -70±√70²-4(1)(-1160)/2
x = -70±√4900+4640)/2
x = -70±(√4900+4640)/2
x = -70±√9540/2
x = -70±97.7/2
x = -70+97.7/2
x = 27.7/2
x = 13.85mph
x ≈ 14 mph
Hence, the speed(s) at which the car gets 9 mpg to the nearest mph is 14mph
Answer:
False
Step-by-step explanation:
Since we already know the value of x lets plug it in and multiply it
-2+11-5(6)=5-6(6)
-2+11-30=5-36
Now lets put them together
9-30=5-36
-21 = -31
Making x=6 false