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3 years ago

(24b^3 + 90b^2) divided by 6b

Mathematics

2 answers:

bulgar [2K]3 years ago

7 0

Answer:

4b^4+15b^3

Step-by-step explanation:

(24b^3+90b^2)

Divide like terms.

24/6=4

90/6=15

(4b^3+15^2)........ Now since you have a "b" left from the 6 you add that b two the previous "b"

There you have it, your answer will be = (4b^4+15^3)

Firlakuza [10]3 years ago

5 0

Answer:

Step-by-step explanation:

(24b^3 + 90b^2) = 6b (4b²+15b)

the quotion is : 4b²+15b

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Could someone answer and explain these please? Thank you!

Oksana_A [137]

Answer 1:

It is given that the positive 2 digit number is 'x' with tens digit 't' and units digit 'u'.

So the two digit number x is expressed as,

$x=(10 \times t)+(1 \times u)$

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The two digit number 'y' is obtained by reversing the digits of x.

So, $y=(10 \times u)+(1 \times t)$

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Now, the value of x-y is expressed as:

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Answer 2:

It is given that the sum of infinite geometric series with first term 'a' and common ratio r<1 = $\frac{a}{1-r}$

Since, the sum of the given infinite geometric series = 200

Therefore, $\frac{a}{1-r}=200$

Since, r=0.15 (given)

$\frac{a}{1-0.15}=200$

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$a=0.85 \times 200$

a=170

The nth term of geometric series is given by $ar^{n-1}$ .

So, second term of the series = $ar^{2-1}$ = ar

Second term = $170 \times 0.15$

= 25.5

So, the second term of the geometric series is 25.5

Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

subtract 8 from both sides.

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