Answer:
x + 2y ≤ 100 and x + 3y ≤ 400
Maximum profit = 6x + 5y.
Step-by-step explanation:
Let there be x number of small dishes and y number of large dishes to maximize the profit.
So, total profit is P = 6x + 5y .......... (1)
Now, the small dish uses 1 cup of sauce and 1 cup of cheese and the large dish uses 2 cups of sauce and 3 cups of cheese.
So, as per given conditions,
x + 2y ≤ 100 ........ (1) and
x + 3y ≤ 400 .......... (2)
Therefore, those are the constraints for the problem. (Answer)
Answer:
2/5m - 1/5
Step-by-step explanation:
distribute the 2 to every term in ()
2(1/5m-2/5) = 2/5m - 4/5
now you have 2/5m -4/5 +3/5
combine like terms variables with variables, non- variables with non-variables. -4/5 + 3/5 = 1/5
2/5m - 1/5
Answer:
y = -x + 12
Step-by-step explanation:
2x + 2y = 24
divide all by 2
x + y = 12
y = -x + 12
