Determine the number of solutions to the following system of equations. y=-3x^2-4x+7 and 3x+2y=18
1 answer:
Answer:
Step-by-step explanation:
y=-3x²-4x+7...(*)
3x+2y=18...(**)
use (*) put the value of y in (**) :
3x +2(-3x²-4x+7)=18
3x-6x²-8x +14 -18 = 0
-6x²-5x- 4 = 0
6x²+5x+4 = 0
delta = b² - 4ac a = 6 b=5 c =4
delta = 5² - 4(6)(4)= 25 -96= -71 negatif
so no reals solution
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