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11Alexandr11 [23.1K]
3 years ago
6

The bulls eye on an archery target has a radius of 3 inches. the entire target has a radius of 9 inches. to the nearest tenth, f

ind the area of the target outside of the bulls eye.
Mathematics
1 answer:
zaharov [31]3 years ago
6 0
Area of a circle = πr²

--------------------------------------------------------
Area of the archery target :
--------------------------------------------------------
Area of the archery target = 9²π

Area of the archery target = 81π

--------------------------------------------------------
Area of the bull's eye :
--------------------------------------------------------
Area of the bull's eye = 3²π

Area of the bull's eye = 9π

--------------------------------------------------------
Area outside the bull's eye :
--------------------------------------------------------
Area of the target outside the bull's eye = 81π - 9π 

Area of the target outside the bullseye =72π or 226.19 in²

--------------------------------------------------------
Answer: 226.19 in²
--------------------------------------------------------
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<u>Z - Intercept</u>
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5, 12, 17, 23, 28, 31, 37, 41, 42, 49, 54, 58, 65, 68, 73, 71

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Upper Quartile = 61.5

IQR = 36

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3 years ago
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