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qwelly [4]
3 years ago
12

If the radius of a circle is increased by a factor of 5, the area increases by a factor of:

Mathematics
1 answer:
Darya [45]3 years ago
7 0

The area will be increased by 25. Option C

Step-by-step explanation:

Given,

The radius of a circle is increased by 5.

To find how much the area will be increased.

Let us take,

The original radius of the circle is = r

The original area = πr²

Again,

After increasing the radius = 5r

Then the area will be = π(5r)² = 25πr²

= 25( original area)

Hence,

The area will be increased by 25.

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How would you do a,b,c,and d
I am Lyosha [343]

a) You are told the function is quadratic, so you can write cost (c) in terms of speed (s) as

... c = k·s² + m·s + n

Filling in the given values gives three equations in k, m, and n.

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Subtracting the first of these equations from the second gives

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Using the next previous equation, we can find m.

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There are a variety of other ways the equation can be found or the system of equations solved. Any way you do it, you should end with

... c = 0.01s² - s + 37

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... c = 0.01·150² -150 +37 = 112 . . . cents/km

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3 years ago
What is the radius of a sphere with a volume of 1/6 pie
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Answer:

\large\boxed{the\ radius\ R=\dfrac{1}{2}}

Step-by-step explanation:

The formula of a volume of a sphere:

V=\dfrac{4}{3}\pi R^3

We have

V=\dfrac{1}{6}\pi

Substitute:

\dfrac{4}{3}\pi R^3=\dfrac{1}{6}\pi        <em>divide both sides by π</em>

\dfrac{4}{3}R^3=\dfrac{1}{6}          <em>multiply both sides by 3</em>

3\!\!\!\!\diagup^1\cdot\dfrac{4}{3\!\!\!\!\diagup_1}R^3=3\!\!\!\!\diagup^1\cdot\dfrac{1}{6\!\!\!\!\diagup_2}

4R^3=\dfrac{1}{2}          <em>divide both sides by 4</em>

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3 years ago
The sides of a triangle have lengths 8, 14, and 15. What kind of triangle is it?
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