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4 years ago

The sum of a negative number, q, and a positive integer, n, is negative. What do you know about q and n?

1 answer:

3 0

| q | > n

1. q + n < 0
2. q + n - n < 0 - n
3. q < -n, where q is negative, and n is positive. Therefore, | q | > n.

Well, think about it. If q + n is less than zero (negative), what kind of relationship can you assume about q and n?

You might be interested in

Greatest common factors 4,8 Can u do a factor tree I need help with it

solong [7]

4. 8
/ \ / \
2 x 2. 4 x 2
/ \
2 x 2

4: 2x2
8: 2x2x2

The GCF is 4

7 0

4 years ago

In the figure, a∥e , m∥n , and m∠2 = 112°.

MatroZZZ [7]

Answer

Find out the m∠6 .

To prove

As given

a∥e , m∥n , and m∠2 = 112°.

As m∥n

a is the transversal (A line that cuts across two or more (usually parallel) lines is called transverasl.)

Thus

∠ 2 = ∠3 ( Corresponding angle property )

∠3 = 112°

Also

a∥e and m is transversal .

∠ 3 = ∠6 = 112 ° ( Corresponding angle property )

Therefore

∠6 = 112°

3 0

3 years ago

Read 2 more answers

A shipment of 11 printers contains 2 that are defective. Find the probability that a sample of size 2, drawn from the 11, will

svet-max [94.6K]

The required probability is $\frac{36}{55}$

Solution:

Given, a shipment of 11 printers contains 2 that are defective.

We have to find the probability that a sample of size 2, drawn from the 11, will not contain a defective printer.

Now, we know that, $\text { probability }=\frac{\text { favourable outcomes }}{\text { total outcomes }}$

Probability for first draw to be non-defective $=\frac{11-2}{11}=\frac{9}{11}$

(total printers = 11; total defective printers = 2)

Probability for second draw to be non defective $=\frac{10-2}{10}=\frac{8}{10}=\frac{4}{5}$

(printers after first slot = 10; total defective printers = 2)

Then, total probability $=\frac{9}{11} \times \frac{4}{5}=\frac{36}{55}$

7 0

3 years ago

What is the perimeter of triangle ABC? 20 units 22 units 24 units 26 units

Alex777 [14]

8[2] + 6[2] = c[2]
64 + 36 = c[2]
100 = c[2]
c = 10

8 + 6 + 10 = 24 units

8 0

3 years ago

Read 2 more answers

Plz Help ASAP!!!!!

xz_007 [3.2K]

Answer:

The hypotenuse is square root of 65

Step-by-step explanation:

a^2 + b^2 = c^2

legs of the right triangle are a and b. Just substitute 4 for a and 7 for b and solve.

4^2+7^2=16+49=65

c^2=65

Find the square root of both sides to get

c=the square root of 65

3 0

3 years ago

Read 2 more answers