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Citrus2011 [14]
2 years ago
11

I'm not quite sure how to do this

Mathematics
1 answer:
Sunny_sXe [5.5K]2 years ago
7 0
0.5t+12=t+10.50------set the equations equal to eachother, with t being the number of toppings
1.5=0.5t----subtract 0.5t from each side and 10.5
t=3---if there are 3 toppings the prices will be the same
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Solve 8x = 1 quick plz
Ulleksa [173]

Answer:

x = 1/8 = 0.125

Step-by-step explanation: Add 1 to both sides of the equation :

8x = 1

Divide both sides of the equation by 8:

x = 1/8 = 0.125

4 0
3 years ago
A rectangle has length 72 cm and it’s width 56 cm. The other rectangle has the same area as this one, but its width is 21 cm. Fi
Kryger [21]

A = l*w

A = 72* 56

A= 4032


4032 = L*21

4032/21 =L

L =192


5 0
3 years ago
A bike was recently marked down $200.00 from its initial price. if you have a coupon for an additional 30% off after the markdow
love history [14]
Should be 525$ if I'm correct
5 0
2 years ago
Read 2 more answers
The LEADING COEFFICIENT OR THE LEADING TERM of 3x - 5x^2y^3 + 6xy + 7 is
cricket20 [7]

The leading term is the term with the highest degree (highest exponent number). Here, the leading term is =》B) - 5x²y³

³ is the highest degree in the given expression.

_____

Hope it helps ⚜

8 0
2 years ago
In a class of 50 students, everyone has either a pierced nose or a pierced ear. The professor asks everyone with a pierced nose
Tems11 [23]

Answer:  3

Step-by-step explanation:

Let E be the event of that student pierces ear and N be the event of that student pierces nose.

Given: n(E\cup N=50)

n(E)=46\\\\n(N)=7

For any two event A and B, we have

n(A\cup B)=n(A)+n(B)-n(A\cap B)

Similarly , n(E\cup N)=n(E)+n(N)-n(E\cap N)

50=46+7-n(E\cap N)\\\\\Rightarrow\ n(E\cap N)=53-50=3

Hence, 3 students have piercings both on their ears and their noses.

7 0
3 years ago
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