B D and E
Hdhdhsmsndnsndnnsjsbdndndndhdjdndndhf
the expression is 27a^3 or (3a)^3
First two rolls have to be 1-4 that is 2/3 chance twice and the third can be 4or 5
2/3*2/3*1/3 + the chance that the fourth is the 5 or 6.
2/3*2/3*2/3*1/3
So the solution is : P=2/3*2/3*1/3 + 2/3*2/3*2/3*1/3
The correct answer to your question is 0.6 !
