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Dennis_Churaev [7]
3 years ago
15

What are the values of x in this equation x^4+12×=4×^2+3×^3

Mathematics
1 answer:
ANTONII [103]3 years ago
4 0
By factorising I got these solutions
X = 0
X = 2
X = - 2
X = 3
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2 times 2 and three forths
Mrrafil [7]
2 *       2 and 3/4.

2 and 3/4 =   (4*2 + 3) / 4 = (8 + 3) / 4 =   11 / 4

2 * 11/4 =   22 / 4 =   5 and 2/4

= 5 and 2/4  or   5 and 1/2 or   5.5

Hope this helps.
6 0
3 years ago
Convert each fraction to a decimal then a percent 4/25 3/11
sashaice [31]

Answer:

4/25=0.16=16%

3/11=0.27=27%

Step-by-step explanation:

5 0
3 years ago
Arrange and write the integers in decreasing order -47, -82, 77, -48
Travka [436]
Decreasing order : 77 ,-47 ,-48 ,-82
6 0
3 years ago
Drag the tiles to the boxes to form correct pairs. Not all tiles will be used. Match the pairs of polynomials to their products.
andreyandreev [35.5K]

The products of the polynomials are:

  • (xy + 9y + 2) * (xy - 3) = x²y² - xy + 9xy² - 27y - 6
  • (2xy + x + y) * (3xy² - y) = 6x²y³ - 2xy² + 3x²y² -xy + 3xy³- y²
  • (x - y) * (x + 3y) = x² + 2xy + 3y²
  • (xy + 3x + 2) * (xy – 9)  = x²y² - 7xy + 3x²y - 27x  - 18
  • (x² + 3xy - 2) * (xy + 3)  = x³y + 3x² + 3x²y² + 7xy - 6
  • (x + 3y) * (x – 3y) = x² - 9y²

<h3>How to evaluate the products?</h3>

To do this, we multiply each pair of polynomial as follows:

<u>Pair 1: (xy + 9y + 2) and (xy – 3)</u>

(xy + 9y + 2) * (xy - 3)

Expand

(xy + 9y + 2) * (xy - 3) = x²y² - 3xy + 9xy² - 27y + 2xy - 6

Evaluate the like terms

(xy + 9y + 2) * (xy - 3) = x²y² - xy + 9xy² - 27y - 6

<u>Pair 2: (2xy + x + y) and (3xy² - y)</u>

(2xy + x + y) * (3xy² - y)

Expand

(2xy + x + y) * (3xy² - y) = 6x²y³ - 2xy² + 3x²y² -xy + 3xy³- y²

<u>Pair 3: (x – y) and (x + 3y) </u>

(x - y) * (x + 3y)

Expand

(x - y) * (x + 3y) = x² + 3xy - yx + 3y²

Evaluate the like terms

(x - y) * (x + 3y) = x² + 2xy + 3y²

<u>Pair 4: (xy + 3x + 2) and (xy – 9) </u>

(xy + 3x + 2) * (xy – 9)

Expand

(xy + 3x + 2) * (xy – 9)  = x²y² - 9xy + 3x²y - 27x + 2xy - 18

Evaluate the like terms

(xy + 3x + 2) * (xy – 9)  = x²y² - 7xy + 3x²y - 27x  - 18

<u>Pair 5: (x² + 3xy - 2) and (xy + 3) </u>

(x² + 3xy - 2) * (xy + 3)

Expand

(x² + 3xy - 2) * (xy + 3)  = x³y + 3x² + 3x²y² + 9xy - 2xy - 6

Evaluate the like terms

(x² + 3xy - 2) * (xy + 3)  = x³y + 3x² + 3x²y² + 7xy - 6

<u>Pair 6: (x + 3y) and (x – 3y)</u>

(x + 3y) * (x – 3y)

Apply the difference of two squares

(x + 3y) * (x – 3y) = x² - 9y²

Read more about polynomials at:

brainly.com/question/4142886

#SPJ1

5 0
2 years ago
emeril used a total of 7 1/4 cups of flour to make three pastries. he used 2 1/4 cups of flour for the first and 2 1/3 cups for
inysia [295]
2 1/3 + 2 1/4 
   = 4 7/12 
7 1/4 - 4 7/12
     =2 2/3
5 0
3 years ago
Read 2 more answers
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