A cross-section is a disc with radius 
![V = \int_0^7 A(x)\, dx = \int_0^7 \pi(x+1)^2dx = \int_0^7 \pi(x^2 + 2x + 1)dx \\ \\ = \pi \left[ \frac{1}{3}x^3 + x^2 + x\right]_0^7 = \pi\left( \frac{1}{3}(7)^3 + 7^2 + 7\right) = \frac{511}{3}\pi](https://tex.z-dn.net/?f=V%20%3D%20%5Cint_0%5E7%20A%28x%29%5C%2C%20dx%20%3D%20%5Cint_0%5E7%20%5Cpi%28x%2B1%29%5E2dx%20%3D%20%5Cint_0%5E7%20%5Cpi%28x%5E2%20%2B%202x%20%2B%201%29dx%20%20%5C%5C%20%5C%5C%0A%3D%20%5Cpi%20%5Cleft%5B%20%5Cfrac%7B1%7D%7B3%7Dx%5E3%20%2B%20x%5E2%20%2B%20x%5Cright%5D_0%5E7%20%3D%20%5Cpi%5Cleft%28%20%5Cfrac%7B1%7D%7B3%7D%287%29%5E3%20%2B%207%5E2%20%2B%207%5Cright%29%20%3D%20%5Cfrac%7B511%7D%7B3%7D%5Cpi)
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Answer: 125 pounds
Step-by-step explanation:
Let's first represent the weight of the black rhinoceros and chimpanzee with variables. We will assign <em>r</em> for the rhinoceros and <em>c</em> for the chimpanzee.
In the question, we were given that the weight for a black rhinoceros is 18 times as much as an average-size chimpanzee. This makes 18 times the chimpanzee's weight equal to the rhinoceros' weight.
Let's put this into an equation.
Now, let's put in the values we know to find the weight of the chimpanzee (i.e., <em>c</em>). We know the weight of a rhinoceros (represented by <em>r</em>) is 2250 pounds, so we can replace it for <em>r</em> in the equation.
To solve this equation, we can divide both sides by 18 to get c by itself and know what it's value is.
We can remove the from the right side to be left with c. We can also divide 2250 by 8 to get the weight of an average-size chimpanzee.
Hence, an average-size chimpanzee weighs 125 pounds.