Step-by-step explanation:

Use the Pythagorean theorem since you are working with a right triangle:
a^2+b^2=c^2a2+b2=c2
The legs are a and b and the hypotenuse is c. The hypotenuse is always opposite the 90° angle. Insert the appropriate values:
0.8^2+0.6^2=c^20.82+0.62=c2
Solve for c. Simplify the exponents (x^2=x*xx2=x∗x ):
0.64+0.36=c^20.64+0.36=c2
Add:
1=c^21=c2
Isolate c. Find the square root of both sides:
\begin{gathered}\sqrt{1}=\sqrt{c^2}\\\\\sqrt{1}=c\end{gathered}1=c21=c
Simplify \sqrt{1}1 . Any root of 1 is 1:
c=c= ±11 *
c=1,-1c=1,−1
The answer is in the following picture, hope it can help you.
Divide 6 2/3 by 4 and you get an x value of 1.67 to double check the answer we can multiply 1 2/3 by 4 and we get 6 2/3
Answer:
clockwise from left, the missing side lengths are 8 m, 13 m, 8 m
Step-by-step explanation:
The perimeter of the figure is the sum of the lengths of its sides. Sides with the same hash mark have the same length, so the perimeter (in meters) is ...
38 = (3x+1) +(2x) +(9) +(2x)
38 = 7x +10
28 = 7x . . . . . . subtract 10
4 = x . . . . . . . . divide by 7
Then the short sides are ...
2x = 2·4 = 8 . . . meters
and the long side is ...
3x+1 = 3·4 +1 = 13 . . . meters