Answer:
33 i think
Step-by-step explanation:
sorry im not that smart but i did the math so it should be 33
<u>Answer-</u>
<em>Cooper will receive </em><em>$12.00</em><em> at the end of the month.</em>
<u>Solution-</u>
Cooper has $1500 in the account now and he deposits an additional $500 at the beginning of the month.
So the total principal becomes 1500+500 = $2000
Given here,
APR = annual percentage rate = 7.2%
But as we have to calculate the monthly interest, so monthly interest rate would be 
Time period = 1 month
So, the interest after 1 month will be,
Therefore, Cooper will receive $12.00 at the end of the month.
Answer:
D) 1/4
Step-by-step explanation:
To solve this, first lets figure out what this variable is. We know we must multiply by t. Well, looking at it, we know that t is one. So lets plug that in.
2*1/2^3(1)
Now we need to figure out what the exponent is that 2 will be raised to. To find that, find out what 3 times one is.
2*1/2^3
Now we need to solve the exponent.
2*1/8
Remember, 2 cubed is eight.
Now we need to find out what 2*1/8 is. To solve this more easily, I am going to turn two into a fraction. This will give us 2/1*1/8. Now we cross multiply, multiplying the numerators by the numerators, and the denominators by the denominators. Remember, the numerator is the top number, and the denominator is the bottom number.
If we do that, we get:
2/8
If we simplify it, we get 1/4. So the asnwer is D) 1/4
Answer:
A system of linear equation could only have 1 solution. This is because the straight lines will only have to meet, cross, or intersect each other once.
A system of linear equation could only have 1 solution. This is because the straight lines will only have to meet, cross, or intersect each other once.
There are many different methods in arriving to the final answer. However, errors cannot be perfectly avoided. One of these errors to mistakenly identify equations as linear. It is important that we know that the equations we are dealing with are of exact or correct characteristics.
Also, if she had used substitution method, she might have mistakenly taken the value of one variable for the other.
