Answer:
(0.4958, 0.7422)
Step-by-step explanation:
Let p be the true proportion of water specimens that contain detectable levels of lead. The point estimate for p is 
. The estimated standard deviation is given by 
. Because we have a large sample, the 90% confidence interval for p is given by 
where 
is the value that satisfies that above this and under the standard normal density there is an area of 0.05. So, the confidence interval is 
, i.e., (0.4958, 0.7422).
The answer is the THIRD option "C"
Im in collage.
Answer:
See below ↓↓↓
Step-by-step explanation:
<u>Subquestion #1</u>
- These angles form a linear pair
- They are supplementary, and add up to 180°
- 2x + 48 = 180
- 2x = 132
- <u>x = 66</u>
<u></u>
<u>Subquestion #2</u>
- These angles are complementary, and add up to 90°
- 35 + 4x + 7 = 90
- 4x + 42 = 90
- 4x = 48
- <u>x = 12</u>
<u></u>
<u>Subquestion #3</u>
- As in #1, they are a linear pair, and are supplementary
- 3x + 54 = 180
- 3x = 126
- <u>x = 42</u>
Answer is B.) (-3,-3) and (2,7)
A. C(13, 10) = 13! = 13·12·11 = 13 · 2 · 11 = 286.C(13, 10) = 13! = 13·12·11 = 13 · 2 · 11 = 286.
B. P(13,10)= 13! =13! =13·12·11·10·9·8·7·6·5·4.
(13−10)! 3!
C. f there is exactly one woman chosen, this is possible in C(10, 9)C(3, 1) =
10! 3!
9!1! 1!2!
10! 3!
8!2! 2!1!
10! 3!
7!3! 3!0!
= 10 · 3 = 30 ways; two women chosen — in C(10,8)C(3,2) =
= 45·3 = 135 ways; three women chosen — in C(10, 7)C(3, 3) =
= 10·9·8 ·1 = 120 ways. Altogether there are 30+135+120 = 285
1·2·3
<span>possible choices.</span><span>
</span>
