Question

the function p(t)=3(e^0.0866t describes how to find the pollution level p(t) in relation to any time t, where t is the number of years after 1970. according to this information, what was the pollution level in 1980? (round your answer to the nearest hundredth) a. 2.38 b. 7.09 c. 7.13 d. 2.36

Answer 1

The pollution level in 1980 was 7.13 to the nearest hundredth ⇒ answer c

Step-by-step explanation:

The function $p(t)=3(e^{0.0866t})$ , where

• p(t) is the population level at any time t
• t is the number of years after 1970

We need to find the pollution level in 1980

∵ $p(t)=3(e^{0.0866t})$

∵ t is the number of years after 1970

∴ t = 1980 - 1970 = 10 years

- Substitute the value of t in the equation above

∴ $p(t)=3(e^{0.0866*10})$

∴ $p(t)=3(e^{0.866})$

∴ p(t) = 7.13214 ≅ 7.13 to the nearest hundredth

The pollution level in 1980 was 7.13 to the nearest hundredth

Learn more:

You can learn more about the functions in brainly.com/question/8520610

#LearnwithBrainly