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3 years ago

Please please please help me with this answer

1 answer:

3 0

Let blueberry = b and poppyseed = p

b + p = 64

b = p + 20

p + 20 + p = 64

2p + 20 = 64

2p = 44

p = 22

b = 22 + 20

b = 42

Jack bought 42 blueberry muffins

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A piece of rope is 54 inches long. It is cut into pieces that are each 9 inches long.

bogdanovich [222]

Answer:

6 pieces of rope

Step-by-step explanation:

if the total is 54 and each are 9 you can make an equation

54= 9 x a

solve for a

to do this you divide 54 by 9

54/9=6

4 0

2 years ago

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Identity the zero of the function y= x (x-4)(x+2)

yulyashka [42]

Answer:

- 2, 0 or 4

Step-by-step explanation:

y = x(x - 4)(x + 2)

x' = 0

x - 4 = 0

x" = 4

x + 2 = 0

x"' = - 2

I hope I helped you.

4 0

3 years ago

Solve the equation for k. -11 = 7 + 2/3k<br><br> A. -24<br> B. -25<br> C. -26<br> D. -27

Kryger [21]

Answer:

k= -27

step-by-step

8 0

3 years ago

Tim is making a fence in the shape of a triangle for his livestock. He wants one side of the triangle to be two times as along a

Ugo [173]

Answer:

Step-by-step explanation:

42 < 21+3x < 84

21 < 3x < 63

7 < x < 21

7 0

3 years ago

HELPPPP<br> please help me answer this question-

erik [133]

Answer:

$\displaystyle GH = 2 \sqrt{30}$

$\displaystyle FH = 2 \sqrt{10}$

$\displaystyle m \angle G = {30}^{ \circ}$

Step-by-step explanation:

<h3>QUESTION-2:</h3>

we are given a right angle triangle

it's a 30-60-90 triangle of which FH is the shortest side

remember that,in case of 30-60-90 triangle the the longest side is twice as much as the shortest side thus

our equation is

$\displaystyle 2FH=4\sqrt{10}$

divide both sides by 2

$\displaystyle\frac{2FH}{2}= \frac{ 4 \sqrt{10} }{2}$

$\displaystyle FH =2 \sqrt{10}$

<h3>Question-1:</h3>

in order to figure out GH we can use Trigonometry because the given triangle is a right angle triangle

as we want to figure out GH we'll use sin function

remember that,

$\displaystyle \sin( \theta) = \frac{opp}{hypo}$

let our opp, hypo and $\theta$ be GH, 4√10 and 60° respectively

thus substitute:

$\displaystyle \sin( {60}^{ \circ} ) = \frac{GH}{4 \sqrt{10} }$

recall unit circle:

$\displaystyle \frac{ \sqrt{3} }{2} = \frac{GH}{4 \sqrt{10} }$

cross multiplication:

$\displaystyle 2 GH = 4 \sqrt{10} \times \sqrt{3}$

simplify multiplication:

$\displaystyle 2 GH = 4 \sqrt{30}$

divide both sides by 2:

$\displaystyle GH = 2 \sqrt{30}$

<h3>QUESTION-3:</h3>

Recall that, the sum of the interior angles of a triangle is 180°

therefore,

$\displaystyle m \angle G + {60}^{ \circ} + {90}^{ \circ} = {180}^{ \circ}$

simplify addition:

$\displaystyle m \angle G + {150}^{ \circ} = {180}^{ \circ}$

cancel 150° from both sides

$\displaystyle m \angle G = {30}^{ \circ}$

6 0

3 years ago

Read 2 more answers