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ivolga24 [154]
3 years ago
12

How to solve by elimination

Mathematics
1 answer:
natka813 [3]3 years ago
5 0
How to solve with elimination: with the equations on the top, add the number on top and bottom if they share a variable such as x. do the rest for all of the numbers.
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1/2 (x + 8) - 15 = - 3
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Answer:

4

Because I took the test and got it correct.

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2 to the -6 power in expotional form and simplified in fractions
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1/64

Step-by-step explanation:

2 ^{ - 6}

1 \div 2 ^{6}

1 \div 64

4 0
3 years ago
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If MO = 7x - 4, and NO = 6x, what is the length of line MN?
Gennadij [26K]

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Step-by-step explanation:

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4 years ago
(1 point) Linear System - Three Variables Solve the following system of equations using Gaussian elimination method. If there ar
EastWind [94]

Answer:

x=\frac{-363}{70} ≈ -5.1857

y=\frac{-192}{35} ≈ -5.4857

z=\frac{313}{84} ≈ 3.7262

Step-by-step explanation:

Rewrite the equation system as:

6x+8y=-75

-3x+6y+6z=5

2x-9y=39

Now, write the system in its augmented matrix form:

\left[\begin{array}{cccc}6&8&0&-75\\-3&6&6&5\\2&-9&0&39\end{array}\right]

applying row reduction process to  its associated augmented matrix:

Swap R1 and R3, and then Swap R1 and R2:

\left[\begin{array}{cccc}-3&6&6&5\\2&-9&0&39\\6&8&0&-75\end{array}\right]

R3+2R1

\left[\begin{array}{cccc}-3&6&6&5\\2&-9&0&39\\0&20&12&-65\end{array}\right]

3R2+2R1

\left[\begin{array}{cccc}-3&6&6&5\\0&-15&12&127\\0&20&12&-65\end{array}\right]

15R3+20R2

\left[\begin{array}{cccc}-3&6&6&5\\0&-15&12&127\\0&0&420&1565\end{array}\right]

Now we have a simplified system:

-3x+6y+6z=5\\0-15y+12z=127\\0+0+420z=1565

-3x+6y+6z=5\hspace{5 mm}(1)\\0-15y+12z=127\hspace{3 mm}(2)\\0+0+420z=1565\hspace{3 mm}(3)

From (3):

z=\frac{313}{84} (4)

Replacing (4) in (2)

y=\frac{-192}{35} (5)

Finally replacing (5) and (4) in (1)

x=\frac{-363}{70}

7 0
3 years ago
Which function below is the inverse of f(x) = x^2-9
USPshnik [31]
To find the inverse
replace f(x) with y
switch all x and y
solve for y
replace y with f⁻¹(x)

f(x)=x^2-9
y=x^2-9
x=y^2-9
x+9=y^2
sqrt both sides
\sqrt{x+9}
replace
f⁻¹(x)=\sqrt{x+9}

that is the inverse
5 0
3 years ago
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