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Anon25 [30]
3 years ago
8

What is the volume of a pyramid 4 cm,4 cm by 12 cm

Mathematics
1 answer:
Alenkinab [10]3 years ago
3 0

<u>Answer: </u>

The volume of pyramid with dimensions 4cm , 4cm by 12cm is \bold{64 \mathrm{cm}^{3}}

<u>Solution: </u>

Volume of a pyramid can be found out by using the below formula,

\bold{v = \frac{1}{3} l w h}

where,

v is the volume of pyramid  

l is the length of pyramid

w is the width of pyramid

h is the height of pyramid

from question, given that l = 4 ; w = 4; h = 12

hence the volume of pyramid for the given dimensions is  

v = \frac{1}{3} \times 4 \times 4 \times 12

= 4 \times 4 \times 4

= 64 \mathrm{cm}^{3}                      

So the volume of pyramid is \bold{64 \mathrm{cm}^{3}}

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7 0
3 years ago
A soccer ball manufacturer wants to estimate the mean circumference of soccer balls within 0.1 in. Determine the minimum sample
leva [86]

Answer:

n=(\frac{z_{\alpha/2} \sigma}{ME})^2 (2)  

The critical value for 95% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.025,0,1)", and we got z_{\alpha/2}=1.96, replacing into formula (2) we got:  

n=(\frac{1.96(0.25)}{0.1})^2 =24.01  

So the answer for this case would be n=25 rounded up to the nearest integer  

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)  

\sigma=0.25 represent the population standard deviation

n represent the sample size (variable of interest)  

Solution to the problem

The confidence interval for the mean is given by the following formula:  

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}  

The margin of error is given by this formula:  

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}} (1)  

And on this case we have that ME =0.1 and we are interested in order to find the value of n, if we solve n from equation (1) we got:  

n=(\frac{z_{\alpha/2} \sigma}{ME})^2 (2)  

The critical value for 95% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.025,0,1)", and we got z_{\alpha/2}=1.96, replacing into formula (2) we got:  

n=(\frac{1.96(0.25)}{0.1})^2 =24.01  

So the answer for this case would be n=25 rounded up to the nearest integer  

8 0
4 years ago
Given the diagram above, m∠Z is:
AveGali [126]

Answer:

120 deg

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The sum of the measures of the interior angles of a quadrilateral is 360 deg.

2t + 2t + t + t = 360

6t = 360

t = 60

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Answer: 120 deg

6 0
3 years ago
The two way table shows the number of houses on the market in the Castillos price range.
DIA [1.3K]

Answer:

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Out of these 30, 24 have 3 bedrooms.  This makes the probability 24/30, which is 0.8.

4 0
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Answer:

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5/6 *2 10/12 figure out how many time 3 goes into 10 about 3.3 repeating

8 0
3 years ago
Read 2 more answers
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